如何从内存缓冲区创建pySDL2映像

Question

我有一个pySimpleGUI程序，它可以从包含JPEG图像的内存缓冲区创建图像。

from PIL import ImageTk
image = ImageTk.PhotoImage( data=buf) # PhotoImage will detect a JPEG format
self.win["-IMAGE-'].update( data=image)

我想将我的应用程序转换为pySDL2。
由于pySimpleGUI和pySDL都是基于PIL的，我本来希望转换很容易，但我找不到从缓冲区创建SDL映像的方法。

有办法吗？

Answer 1

不确定这是否有效，并且未经测试，但可能会让您走上正轨。如果你想了解这次访问背后的更多细节https://rubato.app/.Image类的完整源代码就在那里。

@staticmethod
def from_surface(surface: sdl2.surface.SDL_Surface) -> "Image":
"""
Creates an image from an SDL surface.
Args:
surface: the surface to create the image from.
Returns:
The created image.
"""
# untested
image = Image()
image.image = surface
return image
@staticmethod
def from_buffer(buffer: bytes) -> "Image":
"""
Creates an image from a buffer.
Args:
buffer: bytes containing the image data.
Returns:
The image created from the buffer.
"""
# untested
rw = sdl2.SDL_RWFromMem(buffer, len(buffer))
surface_temp = sdl2.sdlimage.IMG_Load_RW(rw, 1)
if surface_temp is None:
raise Exception(sdl2.sdlimage.IMG_GetError())
surface = sdl2.SDL_ConvertSurfaceFormat(surface_temp, sdl2.SDL_PIXELFORMAT_RGBA8888, 0).contents
sdl2.SDL_FreeSurface(surface_temp)
return Image.from_SDL_Surface(surface)