如何创建跳过功能pygame

Question

我正试图在pygame中创建一种方法，让玩家只需按"escape"就可以跳过教程阶段。然而，当使用以下内容时，我似乎无法使其工作：

for event in pygame.event.get():
if event.type == pygame.K_ESCAPE:
brek2 = True
for event in pygame.event.get():
if event.type == pygame.QUIT:
run = False
run2 = False
brek = True
if brek or brek2:
break
pygame.time.delay(1000)
if brek:
break

如果你需要的话，下面是教程阶段的完整循环：

while run2:
# intro sequence
pygame.event.pump()
fade(screen_width, screen_height, BLACK)
fade(screen_width, screen_height, WHITE)
techi = pygame.transform.scale(pygame.image.load("Techi-Joe.gif"), (75, 75))
bg = pygame.Surface((screen_width, screen_height))
bg.fill(WHITE)
win.blit(pygame.transform.scale(bg, (screen_width, screen_height)), (0, 0))
win.blit(techi, (100, 600))
pygame.display.update()
for event in pygame.event.get():
if event.type == pygame.QUIT:
run = False
run2 = False
pygame.time.delay(1000)
brek2 = False
presss = 1
brek = False
techi_bubble = pygame.transform.scale(pygame.image.load("techi_speech_bubble.png"), (700, 350))
techi_font = pygame.font.Font('Consolas.ttf', 25)
for a in range(len(techi_says)):
win.blit(pygame.transform.scale(bg, (screen_width, screen_height)), (0, 0))
win.blit(techi_bubble, (175, 300))
win.blit(techi, (100, 600))
writeLikeCode(techi_says[a], 235, 350, techi_font, 20)
for event in pygame.event.get():
if event.type == pygame.K_ESCAPE:
brek2 = True
for event in pygame.event.get():
if event.type == pygame.QUIT:
run = False
run2 = False
brek = True
if brek or brek2:
break
pygame.time.delay(1000)
if brek:
break

下面是一些被引用为函数writeLikeCode:的附加代码

techi_says = ["Hello, User!", "My name is Techi-Joe.", "I'm a programmer,", "and this is my first game:",
"Dunk the Chief!", "in Dunk the Chief,", "your main objective", "is to dunk any US president", "you choose",
"in a cold tub of water!", "yay!"]

# writeLikeCode function
def writeLikeCode(string, xpos, ypos, font, fontsize):
for x in range(len(string)):
lstring = split(string)
text = font.render(lstring[x], 1, GREEN)
win.blit(text, (xpos + (x * fontsize), ypos))
pygame.time.delay(50)
pygame.display.update()

这是分割函数：

def split(string):
return [char for char in string]

Answer 1

pygame.event.get()不仅获取事件，还从事件队列中删除事件。如果连续调用pygame.event.get()两次，则第一次调用将检索事件，但第二次调用返回空列表。

for event in pygame.event.get(): # returns the list of events
# [...]
for event in pygame.event.get(): # returns empty list
# [...]

如果事件发生在pygame.event.get()的两次调用之间，则该事件将作为第二次调用接收。但这将是一种罕见的情况。

pygame.K_ESCAPE不是一个事件类型(请参见pygame.event(，它是一个关键字(请参见(pygame.key((
如果要检测是否按下了ESC，则必须检测KEYDOWN事件并评估.key属性是否为K_ESCAPE。例如：

for event in pygame.event.get():
if event.type == pygame.QUIT:
run = False
run2 = False
brek = True
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_ESCAPE:
brek2 = True