字符串到数组的转换[PHP]

Question

如何转换这个字符串的简单问题：

"'One' => 1,'Two' => 2,'Three' => 3,'Four' => 4,"

对于这样的数组：

array['One'] = 1;
array['Two'] = 2;
array['Three'] = 3;
array['Four'] = 4;

Answer 1

使用regex和array_component

preg_match_all('/'(w+)'s*=>s*(d+)/', $str, $m);
print_r(array_combine($m[1], $m[2]));

演示

Answer 2

$string = "'One' => 1,'Two' => 2,'Three' => 3,'Four' => 4,";
$array = explode(',',$string);
foreach($array as $item){
$new_items = explode(' => ', $item);
$key = $new_items[0];
$value = $new_items[1];
$new_array[][$key] = $value;
}
var_dump($new_array);

Answer 3

这里是一个经过测试的解决方案：

$input = "'One' => 1,'Two' => 2,'Three' => 3,'Four' => 4,";
$gen = new ArrayGenerator($input);
$this->assertSame([
'One' => 1,
'Two' => 2,
'Three' => 3,
'Four' => 4,
], $gen->translate());

这里是完整的代码

use PHPUnitFrameworkTestCase;
class FooTest extends TestCase
{
public function testItems()
{
$input = "'One' => 1,'Two' => 2,'Three' => 3,'Four' => 4,";
$parser = new Parser($input);
$this->assertEquals([
"'One' => 1",
"'Two' => 2",
"'Three' => 3",
"'Four' => 4"
], $parser->items());
}
public function testKeyValue()
{
$input = "'One' => 1";
$parser = new KeyValue($input);
$this->assertEquals([
"'One'",
"1",
], $parser->items());
}
public function testKeyValueWithoutQuotas()
{
$input = "'One' => 1";
$parser = new KeyValue($input);
$this->assertEquals([
"One",
"1",
], $parser->itemsWithoutQuotas());
}
public function test()
{
$input = "'One' => 1,'Two' => 2,'Three' => 3,'Four' => 4,";
$gen = new ArrayGenerator($input);
$this->assertSame([
'One' => 1,
'Two' => 2,
'Three' => 3,
'Four' => 4,
], $gen->translate());
}
}
class ArrayGenerator
{
private $input;
public function __construct(string $input)
{
$this->input = $input;
}
public function translate()
{
$parser = new Parser($this->input);
$parsed = $parser->items();
$trans = [];
foreach ($parsed as $item) {
$pair = new KeyValue($item);
$trans[$pair->itemsWithoutQuotas()[0]] = (int) $pair->itemsWithoutQuotas()[1];
}
return $trans;
}
}
class KeyValue
{
private $input;
public function __construct(string $input)
{
$this->input = $input;
}
public function items()
{
$exploded = explode(' => ', $this->input);
return $exploded;
}
public function itemsWithoutQuotas()
{
$items = $this->items();
foreach ($items as $key => $item) {
$items[$key] = str_replace("'", "", $item);
}
return $items;
}
}
class Parser
{
private $input;
public function __construct(string $input)
{
$this->input = $input;
}
public function items()
{
$exploded = explode(',', $this->input);
$exploded = array_filter($exploded, function ($item) {
return $item != "";
});
return $exploded;
}
}

Answer 4

您可以简单地使用php函数array_flicp:

array_flicp—在阵列

碰撞警告：

如果一个值出现多次，则将使用最新的键作为其价值，所有其他都将失去。

示例#2 array_flip((示例：碰撞

<?php
$input = array("a" => 1, "b" => 1, "c" => 2);
$flipped = array_flip($input);
print_r($flipped);
?>

上面的例子将输出：

Array
(
[1] => b
[2] => c
)