如何将字符串中的字符替换n次，每次都替换为给定列表中的新字符

Question

我有以下字符串，其中我想用列表befcodes的每个字符替换A1，然后打印它：

befcodes = ["A1","A2","A3","A4","A5","A6","A7","A8","A9","10","11","12","13","14","15","16","17","18","19","20"]
telegram = "$00;02;A1;00000000*49"

我想得到一个看起来像这样的输出：

$00;02;A1;00000000*49
$00;02;A2;00000000*49
$00;02;A3;00000000*49
......
$00;02;19;00000000*49
$00;02;20;00000000*49

我尝试了一些不同的字符串格式和for循环的方法，但没有完全掌握。你们能帮我吗？

Answer 1

您应该使用str.replace

befcodes = ["A1", "A2", "A3", "A4", "A5", "A6", "A7", "A8", "A9", 
"10", "11", "12", "13", "14", "15", "16", "17", "18", "19", "20"]
telegram = "$00;02;A1;00000000*49"
for code in befcodes:
print(telegram.replace("A1", code))

提供

$00;02;A1;00000000*49
$00;02;A2;00000000*49
$00;02;A3;00000000*49
...
$00;02;18;00000000*49
$00;02;19;00000000*49
$00;02;20;00000000*49