获取Beautfiulsop div类内容

Question

我正在研究beautifulsoup。我想访问div中的文本。我的代码如下。

attack = atackersoup.findAll("div", {"class":"col-12 description"})

我的输出低于

<div class="col-12 description">
A denial of service vulnerability was identified that exists in Apache SpamAssassin before 3.4.2.
</div>

我只想要文本。不要显示div标记。

Answer 1

要从标记中获取text，请使用以下命令：

print(attack.text.strip())

输出：

A denial of service vulnerability was identified that exists in Apache SpamAssassin before 3.4.2.

这是完整的代码：

html = """
<div class="col-12 description">
A denial of service vulnerability was identified that exists in Apache SpamAssassin before 3.4.2.
</div>
"""
from bs4 import BeautifulSoup
soup = BeautifulSoup(html,'html5lib')
div = soup.find('div', class_ = "col-12 description")
print(div.text.strip())

既然你有一个元素列表，你应该循环浏览这些元素并打印文本，比如：

for div in attack:
print(div.text.strip())