使用Python??输出到CGI??错误一直告诉我缺少括号



尝试使用python生成,以使用cgi进行筛选。然而,当我从命令行运行它时,我不断收到一个错误,指出它在print "Content-type:text/htmlrnrn"行缺少括号。

#!/usr/bin/python3
import urllib.request
import json
import os
link = "https://api.nasa.gov/planetary/apod?api_key....."
resp = urllib.request.urlopen(link)
data = resp.read()
print(str(data, 'utf-8'))
returnJson = json.loads(data)
img_url = returnJson['url']
title = returnJson['title']
current_date = returnJson['date']
(filename, headers) = urllib.request.urlretrieve(img_url)
img_file_name = img_url.split('/')[-1]
os.rename(filename, img_file_name)
html = """
<center>
<h1>Astronomy Picture of the Day</h1>
<img src="%s">
<p><b>%s</b></p>
</center>
""" % (img_file_name, title)
html_file_name = 'nasa_apod_%s.html' %current_date
print "Content-type:text/htmlrnrn" **Where it says parenthesis**
print '<html>'
print '<head>'
print '<title>Astronomy Picture of the Day</title>'
print '</head>'
print '<body>'
print '<h1>Astronomy Picture of the Day</h1>'
print '</body>'
print '</html>'

这是因为您使用的是python 3。在python 3中,print是一个函数,而不是一个语句。因此,这意味着您需要在打印的任何内容周围添加括号。

# this will fail in Python 3
print "Content-type:text/htmlrnrn"
# but this will work
print("Content-type:text/htmlrnrn")

正如您所做的,早些时候使用print(str(data, 'utf-8'))

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