Laravel 6 如何在控制器中存储登录的用户 ID

Question

我正在尝试存储记录的用户id，但我收到了这个错误

ErrorException
array_map(): Argument #2 should be an array

这是控制器中的代码

public function store(Request $request)
{
if (!auth()->check()) {
abort(403, 'Only authenticated users can create new posts.');
}
$data = request()->validate([
'id' => $id  = Auth::id(),
'content' => 'required',
'topic' => 'required',
'hashtag' => 'required'
]);
$check = Tweets::create($data);
return Redirect::to("form")->withSuccess('Great! Form successfully submit with validation.');
}

错误在这行代码中。

'id' => $id  = Auth::id(),

我知道这应该是一个字符串，但为了向你解释我正在尝试做什么，我仍然没有找到任何解决方案。

Answer 1

这样做。

public function store(Request $request)
{
if (!auth()->check()) {
abort(403, 'Only authenticated users can create new posts.');
}

$request->validate([
'content' => 'required',
'topic' => 'required',
'hashtag' => 'required'
]);
$data = $request->all();
$data['id'] = Auth::id();
$check = Tweets::create($data);
return Redirect::to("form")->withSuccess('Great! Form successfully submit with validation.');
}

Answer 2

删除此

'id' => $id  = Auth::id(),

并添加

$data['id'] = Auth::id();

之前

$check = Tweets::create($data);

应该可以