我在思考作业的设计时遇到了问题。对于赋值，我将有2个继承层次结构，我需要模拟多个继承功能和交叉乘积，所以robotDog、robotBigDog、robotSmallDog、attakRobotDog等……似乎只是进行多个继承最终会变成9个不同的类文件，这可能不是最好的方法。
例如：
public class dog{
public virtual void bark{ Console.WriteLine("woof")};
}
public class bigDog : dog{
public override void bark{ Console.WriteLine("WOOF")};
}
public class smallDog : dog{
public override void bark{ Console.WriteLine("arf arf")};
}
public class robot{
public virtual void action{ Console.WriteLine("moves")}
}
public class attackRobot : robot{
public virtual void action{ Console.WriteLine("attacks")}
}
public class serviceRobot : robot{
public virtual void action{ Console.WriteLine("serves")}
}
相反，我想做一个包含一只狗和一个机器人的类的双重组合，因为smallDog和bigDog可以代表狗，attakRobot和serviceRobot可以代表机器人。
public class robotDog{
dog myDog;
robot myRobot;
public robotDog(dog typeDog, robot typeRobot){
myDog = typeDog;
myRobot = typeRobot;
}
.
. various functionality
.
}
这是一个实用的设计，使用双重组成，也有一个构造函数，要求一只狗和机器人？或者有不同的思考/处理方式吗？
在C#中不能有多个继承，但可以有多个接口。您可以使用接口来定义狗和机器人的外观，创建一些不同风格的狗和机器人，然后将它们组合到RobotDog类中，该类具有一些可以覆盖的默认值，即
using System;
namespace ConsoleApp1
{
public interface IDog
{
void bark();
}
public interface IRobot
{
void action();
}
public class dog : IDog
{
public virtual void bark() { Console.WriteLine("woof"); }
}
public class bigDog : dog
{
public override void bark() { Console.WriteLine("WOOF"); }
}
public class smallDog : dog
{
public override void bark() { Console.WriteLine("arf arf"); }
}
public class robot : IRobot
{
public virtual void action() { Console.WriteLine("buzz, click"); }
}
public class attackRobot : robot
{
public override void action() { Console.WriteLine("attacks"); }
}
public class serviceRobot : robot
{
public override void action() { Console.WriteLine("attacks"); }
}
public interface IRobotDog : IDog, IRobot
{
IDog dog { get; set; }
IRobot robot { get; set; }
}
public class RobotDog : IRobotDog
{
public IDog dog { get; set; }
public IRobot robot { get; set; }
public RobotDog()
{
dog = new dog();
robot = new robot();
}
public RobotDog(IDog dogType)
{
dog = dogType;
robot = new robot();
}
public RobotDog(IRobot robotType)
{
dog = new dog();
robot = robotType;
}
public RobotDog(IDog dogType, IRobot robotType)
{
dog = dogType;
robot = robotType;
}
public void bark() { dog.bark(); }
public void action() { robot.action(); }
}
class Program
{
static void Main(string[] args)
{
RobotDog robotDog = new RobotDog();
robotDog.bark();
robotDog.action();
robotDog = new RobotDog(new bigDog(), new attackRobot());
robotDog.bark();
robotDog.action();
robotDog = new RobotDog(new bigDog());
robotDog.bark();
robotDog.action();
robotDog = new RobotDog(new attackRobot());
robotDog.bark();
robotDog.action();
robotDog = new RobotDog();
robotDog.dog = new bigDog();
robotDog.bark();
robotDog.action();
}
}
}
我想从Xavier提供的内容中扩展一点。接口只不过是一个"；合同"；。在最简单的形式中，任何继承接口的类都必须声明其中的函数/方法/属性。因此，任何其他试图依赖其定义的公开组件的对象都知道它可以，而且它们不会丢失。现在，作为开发人员，您可以随心所欲地实现它，甚至可以有一个空函数，前提是该函数确实存在，但在其他方面什么都不做。
public interface IDog
{
void bark();
}
public interface IRobot
{
void action();
}
首先，只是简单的狗或机器人。注意每一个执行它们各自的"；REQUIRED"；方法。
public class Dog : IDog
{
public void bark()
{
Console.WriteLine("Woof");
}
}
public class Robot : IRobot
{
public void action()
{
Console.Write("Activate jet pack, fly");
}
}
请注意，机器狗从来没有自己的真正的狗或机器人类。然而，它确实将每个接口的两个单独需求分别实现为两个接口的一个主要类。
public class RoboticDog : IDog, IRobot
{
public void bark()
{
Console.WriteLine("Woof -beep- woof");
}
public void action()
{
Console.Write("Activate jet pack, flying with fur");
}
}
现在，让我们看看它们是如何单独运行的。
static void Main(string[] args)
{
object testDog = new Dog();
object testRobot = new Robot();
object testBoth = new RoboticDog();
WhatCanIDo(testDog);
WhatCanIDo(testRobot);
WhatCanIDo(testBoth);
}
public void WhatCanIDo( object theThing )
{
// Here I am checking if the object is of a class type
// the inherits from IDog. If so, I can type-cast it as such
// and then call its "bark()" method as required to exist from interface.
if (theThing is IDog)
((IDog)theThing).bark();
// likewise if the object has interface of an IRobot
if (theThing is IRobot)
((IRobot)theThing).action();
}
我为您创建了一个小型控制台应用程序，其中包含一些关于如何在需要基类接口时进行捕获的小技巧，反之亦然。
using System;
namespace ConsoleApp6
{
class Program
{
interface IWalkable
{
void Walk(int xAxis, int yAxis);
}
class Robot : IWalkable
{
public int RobotId { get; set; }
public Robot(int robotId)
{
RobotId = robotId;
Console.Write("Robot created! n");
}
public void Walk(int xAxis, int yAxis)
{
Console.WriteLine("Im walking beep boop");
Console.WriteLine("*walks*");
Console.WriteLine($"Ended up in X: {xAxis} y:{yAxis}");
}
}
class BadRobot : Robot
{
public BadRobot(int robotId) : base(robotId)
{
}
}
class Dog : IWalkable
{
public Dog()
{
Console.Write("Dog created! n");
}
public void Walk(int xAxis, int yAxis)
{
Console.WriteLine("Im walking, roof roof");
Console.WriteLine("*walks*");
Console.WriteLine($"Ended up in X: {xAxis} y:{yAxis}");
}
public virtual void Breath()
{
Console.WriteLine("I breath normal");
}
}
class BadDog : Dog
{
public override void Breath()
{
Console.WriteLine("I breath normal");
Console.WriteLine("But then I bark, because im bad");
}
//I can't "extend" an interface
//but I can extend a virtual method from the base class
}
static void Main(string[] args)
{
//three tips over inheritance
//1. If you want to abstract some *behavior*, you probably want an interface:
//for example here, both dogs and robots can walk. They are going to do that
//on their own way, so each need their own proper implementation,
//but the actions is the same thus, the interface
// An interface is meant to group objects over shared functionality
//so for example I can later do something like this
var dog = new Dog();
var badDog = new BadDog();
var badRobot = new BadRobot(1);
// these function doesn't care if its a dog or a robot
void WalkOverThere(IWalkable walkable)
{
//some other code...
walkable.Walk(5, 10);
}
//The key here is that the object pass over parameter implements the IWalk interface
WalkOverThere(badDog);
WalkOverThere(badRobot);
//Please notice that for each class that inherits "IWalkable"
//There will be a new implementation, so in this case, if
//all the robots inherit from the class robot, all will walk the same way
//In that, I cannot extend, or modify how that method is performed in the base
//class from the child class
//2. Now, the case is different when we talk about some functionality that could change
//for any child implementation of the base class. Think about the breath functionality
//A robot can't breathe, but a dog does. And given that every dog breaths differently
//it makes sense to create and virtual method, that means that I can reconfigure how
//the breath method behaves. For example:
dog.Breath();
badDog.Breath();
//3. Another thing that is useful to take into account is that
//whenever I can't create a given object without some piece of information,
//it makes sense to create the necessity of that data in the constructor.
//take for example in this code that I cannot create a robot without a valid int robotId
//This practice enforces me to create a robot like:
//var robot = new Robot(100); where 100 is the id
//var robot = new Robot(); the compile would not allow that
}
}
}