需要编写一个脚本来检查目录中是否存在特定的文件列表
目录/dir look_like 中的文件
ABC_YYYYMDD_EF.txt
GHI_YYYYMDD_LM.txt
列表中有类似的名称
l=[ABC_EF、GHI_LM、PQR_ST、..]
所以必须忽略YYYYMMDD，它可以是这种格式的任何日期，有人能告诉我们应该使用grep还是regex，以及
如何像输出：\
ABC_EF FOUND
GHI_LM FOUND
PQR_ST NOT FOUND
感谢
$ cat tst.sh
#!/usr/bin/env bash
shopt -s extglob nullglob
dir="$1"
names=( ABC_EF GHI_LM PQR_ST )
for name in "${names[@]}"; do
files=( "${dir}/${name%_*}_"+([0-9])"_${name#*_}.txt" )
(( ${#files[@]} )) && result="" || result="NOT "
printf '%st%sFOUNDn' "$name" "$result"
done
$ ls tmp
ABC_19001231_EF.txt GHI_20200102_LM.txt
$ ./tst.sh tmp
ABC_EF FOUND
GHI_LM FOUND
PQR_ST NOT FOUND
使用awk:
awk -v lst="ABC_EF,GHI_LM,PQR_ST" '
BEGIN {
split(lst,map,",") # split the passed variable lst in an array map, using the function split and the delimiter ,
}
END {
for (i in map) { # Loop through each entry in the map array
split(map[i],map1,"_"); # Further split the map values in map1 using _ as the delimiter
res=""; # Initialise a res variable
"find . -maxdepth 1 -regextype posix-extended -regex "^.*"map1[1]"_.*[[:digit:]]+.*_"map1[2]".txt"" | getline res; # Execute a find command and register the result in res using getline
if (res !="") {
print map[i]" FOUND" # If res is not empty, print FOUND, otherwise NOT FOUND.
}
else {
print map[i]" NOT FOUND"
}
close("find . -maxdepth 1 -regextype posix-extended -regex "^.*"map1[1]"_[[:digit:]]{8}_"map1[2]".txt"") # Close the pipe
}
}' <<< /dev/null
一个衬垫：
awk -v lst="ABC_EF,GHI_LM,PQR_ST" 'BEGIN { split(lst,map,",") } END { for (i in map) { split(map[i],map1,"_");res="";"find . -maxdepth 1 -regextype posix-extended -regex "^.*"map1[1]"_.*[[:digit:]]+.*_"map1[2]".txt"" | getline res;if (res !="") { print map[i]" FOUND" } else { print map[i]" NOT FOUND"} close("find . -maxdepth 1 -regextype posix-extended -regex "^.*"map1[1]"_[[:digit:]]{8}_"map1[2]".txt"") } }' <<< /dev/null