我可以识别小写字母和大写字母，并将它们放入字典中.我需要将大小写值连接在一起

Question

我需要知道一个字符显示了多少次，并将结果保存在字典中。例如：CCD_ 1表示"；e"；显示8次；s"；显示7次。我必须使大小写值相同。

我设法弄清楚每个角色显示了多少次。我很难把大写字母和小写字母放在一起而不是分开。

counting_symbols = {}
for letter in "Cryptography is the practice and study of techniques" 
" for secure communication in the presence of third parties" 
" called adversaries. More generally, cryptography is about" 
" constructing and analyzing protocols that prevent third" 
" parties or the public from reading private messages; various " 
"aspects in information security such as data confidentiality, " 
"data integrity, authentication, and non-repudiation are central " 
"to modern cryptography. Modern cryptography exists at the" 
" intersection of the disciplines of mathematics, computer science, " 
"electrical engineering, communication science, and physics. Applications " 
"of cryptography include electronic commerce, chip-based payment cards, " 
"digital currencies, computer passwords, and military communications.":
counting_symbols[letter] = counting_symbols.get(letter, 0) + 1

print(counting_symbols)

这使大写字母和小写字母分开。有人能帮忙让他们联合起来吗？

Answer 1

您只需要添加一行代码即可将字母转换为小写：

counting_symbols = {}
for letter in "Cryptography is the practice and study of techniques" 
" for secure communication in the presence of third parties" 
" called adversaries. More generally, cryptography is about" 
" constructing and analyzing protocols that prevent third" 
" parties or the public from reading private messages; various " 
"aspects in information security such as data confidentiality, " 
"data integrity, authentication, and non-repudiation are central " 
"to modern cryptography. Modern cryptography exists at the" 
" intersection of the disciplines of mathematics, computer science, " 
"electrical engineering, communication science, and physics. Applications " 
"of cryptography include electronic commerce, chip-based payment cards, " 
"digital currencies, computer passwords, and military communications.":
letter = str.lower(letter)
counting_symbols[letter] = counting_symbols.get(letter, 0) + 1
print(counting_symbols)

Answer 2

您可以使用lower((函数降低所有字符，并将其保存到另一个变量中。

使用集合库中的Counter类也是一种很好的做法。Counter对象自动计算字符串中的字符数或列表中的字符串数，并将数据保存在字典中。

text = "Cryptography is the practice and study of techniques"
lower_chars = text.lower()
from collections import Counter
counter = Counter(lower_chars)
print(counter)

Answer 3

计算它们的方式可以更具体。只是给你一个伪代码的例子：

if(letter == ('S' or 's')):
num_s = num_s+1

例如，在函数中，您可以为每个字母复制并粘贴这一行。最后，你可以返回这些数字。我希望你明白我的算法的要点。你可以用很多方法来实现它，我的算法只是非常非常具体。