"Fuse" 2 根字符串在一起

Question

我遇到了一个练习，我必须根据给定字符串的长度添加一些空格。这是我的代码:

public static void main(String[] args) {
final String[] NAMES = {"Spa reine 25cl","Bru plate 50cl","Bru pét 50cl",
"Pepsi","Spa orange", "Schweppes Tonic","Schweppes Agr","Ice Tea","Ice Tea Pêche",
"Jus d'orange Looza", "Cécémel", "Red Bull"};
int[][] stock = {{1,56,200,55},{2,42,200,60},{3,62,200,125},{4,45,200,150},{5,25,200,140},{6,72,200,86},{7,40,200,47},{8,48,200,80},{9,24,150,75},{10,36,200,90},{11,15,100,55},{12,25,80,23}};

for(int i = 0; i<NAMES.length;i++) {
String space1 = placeNumberToRank(NAMES[i], Integer.toString(stock[i][1]), 35);
String space2 = placeNumberToRank(NAMES[i], Integer.toString(stock[i][2]), 40);
String space3 = placeNumberToRank(NAMES[i], Integer.toString(stock[i][3]), 45);
System.out.println(space1);
System.out.println(space2);
System.out.println(space3);
}

}
public static String placeNumberToRank(String originalStr, String numberToPlace, int rank) {
int numberOfSpaces = 0;
numberOfSpaces = rank - originalStr.length() - numberToPlace.length();
return originalStr+" ".repeat(numberOfSpaces)+numberToPlace;
}
}

我需要得到的结果是:(注意最后的数字是对齐的)

Spa reine 25cl                   56  200   55
Bru plate 50cl                   42  200   60
Bru pét 50cl                     62  200  125
Pepsi                            45  200  150
Spa orange                       25  200  140
Schweppes Tonic                  72  200   86
Schweppes Agr                    40  200   47
Ice Tea                          48  200   80
Ice Tea Pêche                    24  150   75
Jus d'orange Looza               36  200   90
Cécémel                          15  100   55
Red Bull                         25   80   23

我现在的结果是:

Spa reine 25cl                   56
Spa reine 25cl                       200
Spa reine 25cl                             55
Bru plate 50cl                   42
Bru plate 50cl                       200
Bru plate 50cl                             60
Bru pét 50cl                     62
Bru pét 50cl                         200
Bru pét 50cl                              125
Pepsi                            45
Pepsi                                200
Pepsi                                     150
Spa orange                       25
Spa orange                           200
Spa orange                                140
Schweppes Tonic                  72
Schweppes Tonic                      200
Schweppes Tonic                            86
Schweppes Agr                    40
Schweppes Agr                        200
Schweppes Agr                              47
Ice Tea                          48
Ice Tea                              200
Ice Tea                                    80
Ice Tea Pêche                    24
Ice Tea Pêche                        150
Ice Tea Pêche                              75
Jus d'orange Looza               36
Jus d'orange Looza                   200
Jus d'orange Looza                         90
Cécémel                          15
Cécémel                              100
Cécémel                                    55
Red Bull                         25
Red Bull                              80
Red Bull                                   23

练习要求调用该方法3次，它需要返回原始str +空格。有没有一种方法可以"融合"?一切都在一起吗?

Answer 1

您应该像这样使用printf()而不是println()。

%-30s编辑字符串左对齐为30个字符的宽度。%4d编辑一个右对齐宽4个字符的整数。%n是操作系统特有的换行符。

for (int i = 0; i < NAMES.length; i++) {
System.out.printf("%-30s %4d %4d %4d%n",
NAMES[i], stock[i][1], stock[i][2], stock[i][3]);
}

输出:

Spa reine 25cl                   56  200   55
Bru plate 50cl                   42  200   60
Bru pét 50cl                     62  200  125
Pepsi                            45  200  150
Spa orange                       25  200  140
Schweppes Tonic                  72  200   86
Schweppes Agr                    40  200   47
Ice Tea                          48  200   80
Ice Tea Pêche                    24  150   75
Jus d'orange Looza               36  200   90
Cécémel                          15  100   55
Red Bull                         25   80   23