在jQuery中使用复选框来切换2个数值

Question

当复选框被选中和未选中时，我如何改变下面的代码在非零值和零值之间切换?看到

$(document).ready(function() {
$('input[type="checkbox"]').click(function() {
var inputValue = $(this).attr("value");
$("." + inputValue).toggle();
});
});

.box {
display: none;
}

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div>
<label><input type="checkbox" name="colorCheckbox" value="n1"> num 1</label>
<label><input type="checkbox" name="colorCheckbox" value="n2"> num 2</label>
<label><input type="checkbox" name="colorCheckbox" value="n3"> num 3</label>
</div>
<div class="n1 box">55000</div>
<div class="n2 box">200</div>
<div class="n3 box">300</div>

https://jsfiddle.net/hcanning/53ye8wf7/

Answer 1

您可以这样做，以获得每个复选框的总和，根据需要进行调整

$(document).ready(function() {
var sum = 0;
$('input[type="checkbox"]').change(function() {
var inputValue = $(this).attr("value");
if(this.checked) {
sum = parseInt(sum) + parseInt($("." + inputValue).text());
}else {
sum = parseInt(sum) - parseInt($("." + inputValue).text());
}
$("#sum").text(sum);
$("." + inputValue).toggle();
});
});

.box {
display: none;
}

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>


<table width="100%">
<tr> 
<td> <label><input type="checkbox" name="colorCheckbox" value="n1"> Show Price</label></td><td><div class="n1 box">55000</div></td>
</tr><tr> 
<td> <label><input type="checkbox" name="colorCheckbox" value="n2"> Show Price</label></td><td><div class="n2 box">200</div></td>
</tr><tr> 
<td> <label><input type="checkbox" name="colorCheckbox" value="n3"> Show Price</label></td><td><div class="n3 box">300</div></td>
</tr>
<tr> 
<td > Total: </td><td><div id="sum">0</div></td>
</tr>