用python编写程序检查给定矩阵是否构成幻方

Question

给你一个矩阵形状的篮子。如果矩阵的大小是N × N，那么你可以在篮子的每个槽中放入的鸡蛋的数量范围是1到N2。你的任务是排列篮子里的鸡蛋，使矩阵的每一行、每一列和对角线的总和保持不变。测试用例供您参考:按篮的用户维度输入，即N = 3所以，你可以在每个槽中放置的鸡蛋数量在1到32(1到9)之间。输入:6 3 65 5 54 7 4

我期待一个python代码来检查一个矩阵是否形成一个魔方。

Answer 1

print("WELCOME! SIR I AM MATHEMAGIX PROGRAM. n I WILL CHECK AND TELL YOU IF YOU CAN ARRANGE THE EGGS IN THE BASKET IN THAT MANNER OR NOT.")
print("n")
print("MAGIC SQUARE :- [A square divided into smaller squares each containing a number,n                 such that the figures in each vertical, horizontal, and diagonal row add up to the same value.]")
print("n")
n=int(input("ENTER THE SIZE OF SQUARE MATRIX SHAPED BASKET YOU HAVE: "))
print("n")
print("ENTER THE NO. OF EGGS BELOW, WHICH YOU WANT IN EACH SECTION OF THE BASKET.")
print("n")
a=[]
for i in range (n):
b=[]
for j in range (n):
j=int(input("Enter The Number of EGGS = "))  
b.append(j)
a.append(b)
if j<=(n*n):
print("n")
print("THE BASKET ARRANGEMENT is ......")
print("n")
for i in range(n):
for j in range (n):
print(a[i][j],end=" ")
print()
sum1d=0
sum2d=0
for i in range(n):
for j in range(n):
if i==j:
sum1d=sum1d+a[i][j]
if i+j==n-1:
sum2d=sum2d+a[i][j]
if sum1d!=sum2d:
z=5
else:
for i in range(n):
sumr=0
sumc=0
for j in range(n):
sumr=sumr+a[i][j]
sumc=sumc+a[j][i]
if sumr!=sum1d:
z=1
elif sumc!=sum1d:
z=1
else:
z=0
if z==0:
print("n")
print("YES SIR! YOU CAN ARRANGE YOUR BASKET WITH THE EGGS IN THAT MANNER.nIT WILL RESULT IN FORMING A MAGIC SQUARE.")
else:
print("n")
print("UH OH! SORRY SIR YOU CAN'T ARRANGE YOUR EGGS LIKE THAT! nIT DOESN'T FORM A MAGIC SQUARE.")
else:
print("n")
print("THE NO. OF EGGS ENTERED IN ANY SLOT HAS MORE VALUE/VALUES GREATER THAN n².(i.e.- OVER THE CAPACITY OF THAT SLOT OF THE BASKET.)n PLEASE RE-RUN THE PROGRAM AND RE-ENTER THE VALUES OF NO. OF EGGS PROPERLY !")