Bash脚本在Jenkins声明式管道中不接受第二个参数

Question

下面是我获取telnet状态的脚本

#!/bin/bash
IP=$1;
PORT=$2;
exec 3> /dev/tcp/$IP/$PORT
if [ $? -eq 0 ];then echo "PortOpen";else echo "PortClosed";fi

我正在调用管道阶段中的函数

def telnetTest (namespace, release, port) {
script {
// Getting Service IP
def serviceIP = sh (
returnStdout: true,
script: "kubectl get svc -n ${namespace} | grep ${release} | awk '{print $4}'"
)
echo "ServiceIP: ${serviceIP}"
// Checking Service IP is Exsisting ?
if (serviceIP.equals('')) {
echo "ERROR: Getting service IP failed"
sh 'exit 1'
}
// Telnet Testing 
sh "chmod +x telnetPort.sh"

def telnetTesting = sh (
returnStdout: true,
script: "./telnetPort.sh ${serviceIP} ${port}"
)
echo "${telnetTesting}"        
}

}

管道阶段

Pipeline {
environment {
NAMESPACE = default
RELEASE = test
PORT = 9040
}
stages {
stage ('Telnet Test') {
steps {
script {
telnetTest ("${NAMESPACE}", "${RELEASE}", "${PORT}")
}
}
}
}
}

现在它只接受传递给脚本的第一个参数谁能告诉我为什么?我哪里错了

Answer 1

在你的函数中，你写的是port，在定义行中，你写的是PORT。