我是SQL Server的新手,我有3个表考虑一个员工表
<表类>
empid
名称
位置
tbody><<tr>1 abc 美国 2efg 英国 表类>
请尝试一下
select e.empid, e.location, h.holidaycode, [date], max([type])
from employee e inner join location_table l
on e.location=l.location
inner join holidaytable h
on l.holidaycode=h.holidaycode
where e.empid=2 and h.[date]='2022-01-01'
group by e.empid, e.location, h.holidaycode, [date]
的例子:
Schema和insert语句:
create table employee(empid int, name varchar(50), location varchar(50));
insert into employee values(1, 'abc', 'USA');
insert into employee values(2, 'efg', 'UK');
create table location_table(location varchar(50),holidaycode varchar(50));
insert into location_table values('uk','uk1');
insert into location_table values('usa','usa1');
create table holidaytable(holidaycode varchar(50), [date] date, [type] varchar(50));
insert into holidaytable values('uk1', '2022-01-01', 'LM');
insert into holidaytable values('uk1', '2022-01-01', 'RMC');
查询:
select e.empid, e.location, h.holidaycode, [date], max([type]) [type 1]
from employee e inner join location_table l
on e.location=l.location
inner join holidaytable h
on l.holidaycode=h.holidaycode
where e.empid=2 and h.[date]='2022-01-01'
group by e.empid, e.location, h.holidaycode, [date]
输出:
您可以使用ROW_NUMBER
只获取每个分组的第一行。
使用ORDER BY type DESC
或ORDER BY CASE WHEN type = 'RMC' THEN 1 ELSE 2 END
SELECT
e.empid,
e.location,
l.holidaycode,
h.date,
h.type
FROM employee e
JOIN location l ON l.location = e.location
JOIN (
SELECT *,
rn = ROW_NUMBER() OVER (PARTITION BY h.holidaycode, h.date ORDER BY h.type DESC)
FROM holiday h
) h ON h.holidaycode = l.holidaycode AND h.rn = 1
WHERE h.date = '2022-01-01';
,db<的在小提琴