如何将hydra配置转储为带有' _target_ '字段的yaml

Question

从python数据类实例化hydra配置。例如

from dataclasses import dataclass
from typing import Any
from hydra.utils import instantiate
class Model():
def __init__(self, x=1):
self.x = x
@dataclass
class MyConfig:
model: Any
param: int
static_config = MyConfig(model=Model(x=2), param='whatever')
instantiated_config = instantiate(static_config)

现在，我想把这个配置转储为一个yaml，包括Hydra用来重新实例化配置中指向的对象的_target_字段。我想避免不得不编写自己的逻辑来编写那些_target_字段，我想一定有一些hydra实用程序可以做到这一点，但我似乎无法在文档中找到它。

Answer 1

参见OmegaConf.to_yaml和OmegaConf.save:

from omegaconf import OmegaConf
# dumps to yaml string
yaml_data: str = OmegaConf.to_yaml(my_config)
# dumps to file:
with open("config.yaml", "w") as f:
OmegaConf.save(my_config, f)
# OmegaConf.save can also accept a `str` or `pathlib.Path` instance:
OmegaConf.save(my_config, "config.yaml")

请参见Hydra-Zen项目，该项目提供自动生成OmegaConf对象(可以保存为yaml)。