所以我试图在我的程序中实现错误捕捉器，但我不能100%确定它们的实际工作方式，我在YouTube上看了一些教程，但它们向我解释的方式并不是100%清楚，因此，我在这里真正想做的是，试图在代码的结尾添加一些东西，如果你插入一个他无法识别的字母或数字，他不会给我们一个错误，但他会给我们一条信息，告诉我们出了什么问题。
我试图用if语句制作一个更容易的版本，但我认为这并不完全适合这段代码，因为我必须用if语句重写所有内容，而且我不确定实际如何工作。
我认为可以工作的代码
它不让我把代码放在这里：C
我试图实现错误处理的代码
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc= new Scanner(System.in);
System.out.println("Insert number of students: ");
String student = sc.nextLine();
int studenti = Integer.parseInt(student);
int[] array = new int[studenti];
for (int i = 0; i<studenti;i++)
{
System.out.println("Insert a score in percentage: ");
String score = sc.nextLine();
array[i]= Integer.parseInt(score);
}
System.out.println("nPercentages are: ");
int sum = 0; // Added a variable for sum
for (int i = 0; i < studenti; i++) {
System.out.println((array[i]) + "%");
sum += array[i]; // maintaining sum
}
int average = sum / array.length; // calculating the average
System.out.println("nThe Average Score is: " + average + "%");
}
使用try/catch块。
public static void main(String[] args) {
Scanner sc= new Scanner(System.in);
System.out.println("Insert number of students: ");
String student = sc.nextLine();
try{
int studenti = Integer.parseInt(student);
int[] array = new int[studenti];
for (int i = 0; i<studenti;i++)
{
System.out.println("Insert a score in percentage: ");
String score = sc.nextLine();
array[i]= Integer.parseInt(score);
}
System.out.println("nPercentages are: ");
int sum = 0; // Added a variable for sum
for (int i = 0; i < studenti; i++) {
System.out.println((array[i]) + "%");
sum += array[i]; // maintaining sum
}
int average = sum / array.length; // calculating the average
System.out.println("nThe Average Score is: " + average + "%");
}catch(Exception ex){
System.out.println("Error, details: " + ex.Message());
}
您可以使用许多"Exception"，例如numberFormatException。
错误处理其实并没有那么复杂。这是关于知道在try语句的作用域中抛出了什么类型的异常。当您将光标放在正在使用的方法上时，IDE通常可以获得这些信息。
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
try {
System.out.println("Insert number of students: ");
int student = sc.nextInt(); // note Im using a method specific for int, instead of parsing
int[] array = new int[student];
for (int i = 0; i < student; i++) {
System.out.println("Insert a score in percentage: ");
String score = sc.nextLine();
array[i]= Integer.parseInt(score);
}
System.out.println("nPercentages are: ");
int sum = 0;
for (int i = 0; i < student; i++) {
System.out.println((array[i]) + "%");
sum += array[i];
}
int average = sum / student; // student == array.length
System.out.println("nThe Average Score is: " + average + "%");
} catch (InputMismatchException | NumberFormatException exception) {
// This will catch errors due wrong input (ie user entered a letter
// instead of a digit) and execute the code within this block.
// Another possible Exception thrown is IllegalStateException.
System.err.println("There was an error. Details:");
exception.printStackTrace(System.err); // remove if you don't want to see the error trace
} finally { // this will get executed whether your code had errors or not
sc.close(); // dont forget to close your scanner
}
}
如果您的IDE没有向您显示有关方法的信息，则可能没有对其进行文档记录，或者您没有导入所述文档。对于这种情况，只需谷歌一下，你就会发现例外情况。例如，此链接向您显示有关Scanner.nextInt()和Integer.parseInt(。的信息
代码中损坏的部分除以零。处理异常
try {
int average = sum / array.length; // throw Exception
}
catch (ArithmeticException e) {
System.out.println(
"Divided by zero operation cannot possible");
}