如何更改代码，使程序跳过用户输入No后的选项?

Question

我想让程序跳转到"输入另一个?"提示"快递?"后输入N。我该怎么做呢?现在，当输入N时，仍然提示&;Long distance?&;

下面是当前批次的代码。上下文:这是代码的数据输入部分，用户输入被添加到数组列表中。

String input=null;

//data entry (user input + adding to arraylist)
do {

System.out.println("Enter parcel code: ");
String pCode=kboard.next();

System.out.println("Enter parcel length: ");
double pLength=kboard.nextDouble();

System.out.println("Enter parcel width: ");
double pWidth=kboard.nextDouble();

System.out.println("Enter parcel height: ");
double pHeight=kboard.nextDouble();

System.out.println("Enter parcel weight: ");
double pWeight=kboard.nextDouble();

Parcel parcel=new Parcel(pCode, pLength, pWidth, pHeight, pWeight);

List.add(parcel);

System.out.println("Express parcel? Y/N: ");
String expressP=kboard.nextLine();
input=kboard.next();

System.out.println("Long distance parcel? Y/N: ");
String longDist=kboard.nextLine();
input=kboard.next();

System.out.println("Do you want to enter another parcel record? Y/N: ");
input=kboard.next();

}

while (input.toLowerCase().equals("y"));

Answer 1

使用'if-else快递包裹

System.out.println("Express parcel? Y/N: ");
String expressP=kboard.nextLine();
input=kboard.next();
if(ip.equalsIgnoreCase("Y").  //This will execute only if previous resp is Yes
{ 
System.out.println("Long distance parcel? Y/N: ");
String longDist=kboard.nextLine();
input=kboard.next();
}
System.out.println("Do you want to enter another parcel record? Y/N: ");
input=kboard.next();

这样，如果用户输入N或N，它将要求下一次迭代跳过包裹距离的代码。

Answer 2

试试下面的代码:

String input=null;
//data entry (user input + adding to arraylist)
do {
System.out.println("Enter parcel code: ");
String pCode=kboard.next();
System.out.println("Enter parcel length: ");
double pLength=kboard.nextDouble();
System.out.println("Enter parcel width: ");
double pWidth=kboard.nextDouble();
System.out.println("Enter parcel height: ");
double pHeight=kboard.nextDouble();
System.out.println("Enter parcel weight: ");
double pWeight=kboard.nextDouble();
/*Parcel parcel=new Parcel(pCode, pLength, pWidth, pHeight, pWeight);
List.add(parcel);*/
System.out.println("Express parcel? Y/N: ");
String expressP=kboard.next();
if (expressP.equalsIgnoreCase("Y")) {
System.out.println("Long distance parcel? Y/N: ");
String longDist = kboard.nextLine();
input = kboard.next();
}
System.out.println("Do you want to enter another parcel record? Y/N: ");
input=kboard.next();
}
while (input.toLowerCase().equals("y"));

您需要添加一个额外的if来检查用户是否输入了Y