如果我有一个像这样的项目数组
[
{id: 1, name: 'Sam', gender: 'boy'},
{id: 2, name: 'Mary', gender: 'girl'},
{id: 3, name: 'Sam', gender: 'boy'}
]
仅根据姓名和性别匹配,如何将其简化为以下结果?
[
{id: 1, name: 'Sam', type: 'boy'},
{id: 2, name: 'Mary', type: 'girl'}
]
让我们试试
items$.pipe(map(this.uniqueArray))
uniqueArray(array: any[]): any[] {
return array.filter(
(item, index, self) =>
index === self.findIndex((x) => x.name === item.name)
);
}
https://stackblitz.com/edit/angular-isqjpa?file=src/app/hello.component.ts