我对Oracle和Clob数据类型非常陌生。
我们有一个名为ABC的表,它有一列CLOB数据类型。
The Clob Column";MyClob";具有以下文本数据:
{ "UD_1":"John", "UD_2":"Doe", "UD_3":"1011=John Doe"}
当我使用以下查询查询表"ABC"时,
Select Id,
JSON_VALUE(MyClob, '$.UD_1') FirstName
JSON_VALUE(MyClob, '$.UD_2') LastName
JSON_VALUE(MyClob, '$.UD_3') Status
From Abc
我得到下表:
Id FirstName LastName Status
1 John Doe 1011=John Doe
2 Jack Ham 2022=Jack Ham
我只想更新其中一行的"UD_3"值。我不知道如何编写更新查询来更新Clob列中的文本。
您可以使用JSON_MERGEPATCH对JSON执行更新。要使用JSON_MERGEPATCH
,在第二个参数中,您需要传递一个要更新的键/值对的JSON对象。请参阅下面的示例。
需要注意的另一点是,JSON_MERGEPATCH
的返回值将从JSON中删除任何不必要的空格。
SQL> CREATE TABLE sampletable
2 (
3 id,
4 myclob
5 )
6 AS
7 SELECT 1,
8 EMPTY_CLOB ()
9 || '{ "UD_1":"John", "UD_2":"Doe", "UD_3":"1011=John Doe"}'
10 FROM DUAL
11 UNION ALL
12 SELECT 2,
13 EMPTY_CLOB ()
14 || '{ "UD_1":"Jack", "UD_2":"Ham", "UD_3":"2022=Jack Ham"}'
15* FROM DUAL;
Table SAMPLETABLE created.
SQL> SELECT *
2 FROM sampletable t
3 CROSS JOIN
4 JSON_TABLE (
5 t.myclob,
6 '$'
7 COLUMNS (firstname VARCHAR2 PATH '$.UD_1',
8 lastname VARCHAR2 PATH '$.UD_2',
9* status VARCHAR2 PATH '$.UD_3'));
ID MYCLOB FIRSTNAME LASTNAME STATUS
_____ _________________________________________________________ ____________ ___________ ________________
1 { "UD_1":"John", "UD_2":"Doe", "UD_3":"1011=John Doe"} John Doe 1011=John Doe
2 { "UD_1":"Jack", "UD_2":"Ham", "UD_3":"2022=Jack Ham"} Jack Ham 2022=Jack Ham
SQL> UPDATE sampletable
2 SET myclob = json_mergepatch (myclob, '{"UD_3":"3033-Devp"}')
3* WHERE id = 1;
1 row updated.
SQL> SELECT *
2 FROM sampletable t
3 CROSS JOIN
4 JSON_TABLE (
5 t.myclob,
6 '$'
7 COLUMNS (firstname VARCHAR2 PATH '$.UD_1',
8 lastname VARCHAR2 PATH '$.UD_2',
9* status VARCHAR2 PATH '$.UD_3'));
ID MYCLOB FIRSTNAME LASTNAME STATUS
_____ _________________________________________________________ ____________ ___________ ________________
1 {"UD_1":"John","UD_2":"Doe","UD_3":"3033-Devp"} John Doe 3033-Devp
2 { "UD_1":"Jack", "UD_2":"Ham", "UD_3":"2022=Jack Ham"} Jack Ham 2022=Jack Ham