有人明白这段代码的错误吗?似乎是最后一行代码有问题。
TypeError:/: 'str'和'str'不支持的操作数类型
BS = requests.get(f'https://financialmodelingprep.com/api/v3/balance-sheet-statement/{company}?apikey={demo}').json()
# get income statement as % of revenue for future predictions and forecast 5 next IS years
income_statement = pd.DataFrame.from_dict(IS[0], orient='index')
income_statement = income_statement[5:26]
income_statement.columns = ['current_year']
income_statement['as_%_of_revenue'] = income_statement /income_statement.iloc[0]
income_statement['as_%_of_revenue'] = income_statement /income_statement.iloc[0]
转换成int，然后给我
income_statement['as_%_of_revenue'] = int((income_statement) / int(income_statement)).iloc[0]
TypeError: int() argument must be a string, a bytes-like object or a number, not 'DataFrame'
尽管更多的研究可能已经解决了这个问题:
您正在尝试划分两个数字(我猜)，但它们被格式化为str。试着把它们转换成可整除的东西，比如int或float，简单的例子:
**income_statement['as_%_of_revenue'] = int(income_statement) / int(income_statement.iloc[0]**)
更新似乎你正试图将pandas Dataframe中的一行中的值除以该行中的另一个数字。如果你有Dataframedf = pd.DataFrame(data=([100, 200], [500, 500])):
0 1
0 100 200
1 500 500
您可以像这样添加一个包含第一列比第二列的百分比的列:df['as_%'] = (df[0] / df[1])*100。结果是:
0 1 as_%
0 100 200 50.0
1 500 500 100.0
这一行缺少
net_income = IS[0]['netIncome']
这就是为什么"我想用最后一行实现什么"这个问题不清楚的原因。因此整个代码是:
net_income = IS[0]['netIncome']
BS = requests.get(f'https://financialmodelingprep.com/api/v3/balance-sheet-statement/{company}?apikey={demo}').json()
# get income statement as % of revenue for future predictions and forecast 5 next IS years
income_statement = pd.DataFrame.from_dict(IS[0], orient='index')
income_statement = income_statement[5:26]
income_statement.columns = ['current_year']
income_statement['as_%_of_revenue'] = income_statement /income_statement.iloc[0]
我想要实现的是将损益表除以收入(销售额)=收入/收入(本年)。这个结果将给我一个预测未来几年收入的百分比，这是一个乘数。
分割前的数据是这样的
问题是income_statement被定义为一个类，因为数据框
<class 'pandas.core.frame.DataFrame'>
current_year
period FY
revenue 495308000
costOfRevenue 43839000
grossProfit 451469000
grossProfitRatio 0.911491
researchAndDevelopmentExpenses 101117000
generalAndAdministrativeExpenses 101439000
sellingAndMarketingExpenses 252820000
otherExpenses 0
operatingExpenses 455376000
costAndExpenses 499215000
interestExpense 38119000
depreciationAndAmortization 12101000
ebitda 8.194e+06
ebitdaratio 0.0165432
operatingIncome -3.907e+06
operatingIncomeRatio -0.00788802
totalOtherIncomeExpensesNet 14382000
incomeBeforeTax -27645000
incomeBeforeTaxRatio -0.0558138
incomeTaxExpense 0
我刚刚接触python(3个月)，所以我不确定所有简单的问题，我猜
谢谢你的帮助
更新我现在就这样做了(即使这会花费我更多的时间)
i declare also revenue
net_income = IS[0]['netIncome']
revenue = IS[0]["revenue"]
，像这样计算
income_statement['as_%_of_revenue'] = (net_income/revenue)*100
向前看，如果这引起任何进一步的问题，我猜
数据现在是这样的
current_year as_%_of_revenue
period FY -4.920978
revenue 495308000 -4.920978
costOfRevenue 43839000 -4.920978
grossProfit 451469000 -4.920978
grossProfitRatio 0.911491 -4.920978
researchAndDevelopmentExpenses 101117000 -4.920978
generalAndAdministrativeExpenses 101439000 -4.920978
sellingAndMarketingExpenses 252820000 -4.920978
otherExpenses 0 -4.920978
operatingExpenses 455376000 -4.920978
costAndExpenses 499215000 -4.920978
interestExpense 38119000 -4.920978
depreciationAndAmortization 12101000 -4.920978
ebitda 8.194e+06 -4.920978
ebitdaratio 0.0165432 -4.920978
operatingIncome -3.907e+06 -4.920978
operatingIncomeRatio -0.00788802 -4.920978
totalOtherIncomeExpensesNet 14382000 -4.920978
incomeBeforeTax -27645000 -4.920978
incomeBeforeTaxRatio -0.0558138 -4.920978
incomeTaxExpense 0 -4.920978
netIncome -24374000 -4.920978
很简单，你可以试试这个&;income_statement = income_statement[6:26]&;