我如何为我的文档上的字段创建默认映射，这将不会在Elasticsearch的下一个主要版本中冗余? &

Question

我正在使用Elasticsearch 7.14.0，其中映射类型已被删除。

根据这个问题，我了解到PUT文档的通用URI是/[index]/_doc/[id]。

我想在name字段上为我的文档创建一个默认映射:

curl -X PUT "localhost:9200/products?pretty" -H 'Content-Type: application/json' -d'
{
"mappings":{
"properties":{
"name":{
"analyzer":"edge_ngram_analyzer",
"search_analyzer":"standard",
"type":"text"
}
}
},
"settings":{
"analysis":{
"filter":{
"edge_ngram":{
"type":"edge_ngram",
"min_gram":"2",
"max_gram":"25",
"token_chars":[
"letter",
"digit"
]
}
},
"analyzer":{
"edge_ngram_analyzer":{
"filter":[
"lowercase",
"edge_ngram"
],
"tokenizer":"standard"
}
}
}
}
}
'

但是创建一个新文档并不应用分析器:

curl -X PUT "localhost:9200/products/_doc/1?pretty" -H 'Content-Type: application/json' -d'
{
"name": "Toast"
}
'
curl -X GET "localhost:9200/products/_search?pretty"
{
"took" : 1026,
"timed_out" : false,
"_shards" : {
"total" : 1,
"successful" : 1,
"skipped" : 0,
"failed" : 0
},
"hits" : {
"total" : {
"value" : 1,
"relation" : "eq"
},
"max_score" : 1.0,
"hits" : [
{
"_index" : "products",
"_type" : "_doc",
"_id" : "1",
"_score" : 1.0,
"_source" : {
"name" : "Toast"
}
}
]
}
}

我尝试在_doc类型下创建映射，但得到以下错误:

curl -X PUT "localhost:9200/products?pretty" -H 'Content-Type: application/json' -d'
{
"mappings":{
"_doc":{
"properties":{
"name":{
"analyzer":"edge_ngram_analyzer",
"search_analyzer":"standard",
"type":"text"
}
}
}
},
"settings":{
"analysis":{
"filter":{
"edge_ngram":{
"type":"edge_ngram",
"min_gram":"2",
"max_gram":"25",
"token_chars":[
"letter",
"digit"
]
}
},
"analyzer":{
"edge_ngram_analyzer":{
"filter":[
"lowercase",
"edge_ngram"
],
"tokenizer":"standard"
}
}
}
}
}
'
{
"error" : {
"root_cause" : [
{
"type" : "illegal_argument_exception",
"reason" : "The mapping definition cannot be nested under a type [_doc] unless include_type_name is set to true."
}
],
"type" : "illegal_argument_exception",
"reason" : "The mapping definition cannot be nested under a type [_doc] unless include_type_name is set to true."
},
"status" : 400
}

然而，我读到过:

Elasticsearch 8. x:不再支持在请求中指定类型。删除include_type_name参数

我如何为我的文档上的字段创建默认映射，这将不会在Elasticsearch的下一个主要版本中冗余?

Answer 1

这个问题是由于我对ES的一个误解造成的。我认为搜索返回的结果应该包括对任何字段的底层分析。当我执行部分匹配搜索时，将正确返回文档，因此上面的映射按预期工作:

curl -X GET "localhost:9200/products/_search?pretty" -H 'Content-Type: application/json' -d'
{
"query": {
"match": {
"name": "To"
}
}
}
'
{
"took" : 7,
"timed_out" : false,
"_shards" : {
"total" : 1,
"successful" : 1,
"skipped" : 0,
"failed" : 0
},
"hits" : {
"total" : {
"value" : 1,
"relation" : "eq"
},
"max_score" : 0.41501677,
"hits" : [
{
"_index" : "products",
"_type" : "_doc",
"_id" : "1",
"_score" : 0.41501677,
"_source" : {
"name" : "Toast"
}
}
]
}
}