如何在一列中获取两个日期之间的确切年,月,日期oracle sql
下面是我的查询,目前我的输出显示为0年11个月30天,但我需要输出像1年0个月0天
select trunc(months_between(lease.lease_end_date,(lease.lease_start_date)) / 12) || ' Years ' || trunc(months_between(lease.lease_end_date,(trunc(lease.lease_start_date,'YY'))) - (trunc(months_between(lease.lease_end_date,(trunc(lease.lease_start_date,'YY'))) / 12) * 12)) || ' Months' ||' '|| ( trunc(lease.lease_end_date)- add_months((trunc(lease.lease_start_date,'YY')), trunc(months_between(lease.lease_end_date,(trunc(lease.lease_start_date,'YY')))))) || ' Days '
from dual
这是我的查询,但我的输出显示为0年11个月30天,但我想要1年0个月0天
您可以使用:
SELECT lease_start_date,
lease_end_date,
EXTRACT(YEAR FROM year_months) || ' years '
|| EXTRACT(MONTH FROM year_months) || ' months '
|| EXTRACT(DAY FROM day_time) || ' days '
|| EXTRACT(HOUR FROM day_time) || ' hours '
|| EXTRACT(MINUTE FROM day_time) || ' minutes '
|| EXTRACT(SECOND FROM day_time) || ' seconds' AS difference
FROM (
SELECT lease_start_date,
lease_end_date,
(lease_end_date - lease_start_date) YEAR TO MONTH AS year_months,
(lease_end_date - ADD_MONTHS(lease_start_date, TRUNC(MONTHS_BETWEEN(lease_end_date, lease_start_date)))) DAY TO SECOND AS day_time
FROM lease
)
对于样本数据:
CREATE TABLE lease (lease_start_date, lease_end_date) AS
SELECT DATE '2020-02-29', DATE '2021-03-01' FROM DUAL UNION ALL
SELECT DATE '2020-02-29', DATE '2021-02-28' FROM DUAL UNION ALL
SELECT DATE '2020-02-28', DATE '2021-02-28' FROM DUAL UNION ALL
SELECT DATE '2020-02-01', DATE '2020-02-01' + INTERVAL '12:34:56' HOUR TO SECOND FROM DUAL
输出:
LEASE_START_DATE LEASE_END_DATE DIFFERENCE 2020-02-29 00:00:00 2021-03-01 00:00:00 1年0个月1天0小时0分0秒 2020-02-29 00:00:00 2021-02-28 00:00:00 1年0个月0天0小时0分0秒 2019-02-28 00:00:00 2019-02-28 00:00:00 1年0个月0天0小时0分0秒 2020-02-01 00:00:00 2020-02-01 12:34:56 0年0月0天12小时34分56秒