在Python中不使用itertools包将两个列表中的每个元素组合成一个元组

Question

我是新手，我有两个列表，并希望将它们组合成一个元组，随机所有可能的元素，而不使用任何数据包，如itertools数据包．就像这个例子:

list1 = ["a", "b", "c"]
list2 = ["wow", 2]

和输出:

>>> new_tuple = (["a","wow"],["b","wow"],["c","wow"],["a",2],["b",2],["c",2])

你能帮我吗?提前谢谢你

Answer 1

Python3使用列表生成器的一行代码

list1 = ['a', 'b', 'c']
list2 = ['wow', 2]
new_tuple = tuple([l1, l2] for l2 in list2 for l1 in list1)
print(new_tuple)
# (['a', 'wow'], ['b', 'wow'], ['c', 'wow'], ['a', 2], ['b', 2], ['c', 2])

Answer 2

您可以使用itertools

import itertools
list1 = ["a", "b", "c"]
list2 = ["wow", 2]
c = tuple(itertools.product(list1, list2))
print(c)

Answer 3

您可以使用itertools来进行您请求的排列，如下所示:

import itertools
list1 = ["a", "b", "c"]
list2 = ["wow", 2]
all_combinations = []
list1_permutations = itertools.permutations(list1, len(list2))
for each_permutation in list1_permutations:
zipped = zip(each_permutation, list2)
all_combinations.append(list(zipped))
print(all_combinations)

输出如下:

[[('a', 'wow'), ('b', 2)], [('a', 'wow'), ('c', 2)], [('b', 'wow'), ('a', 2)], [('b', 'wow'), ('c', 2)], [('c', 'wow'), ('a', 2)], [('c', 'wow'), ('b', 2)]]```

Answer 4

import random
list1 = ["a", "b", "c"]
list2 = ["wow", 2]
new_tuple = ()
for x in (len(list1)+len(list2)):
randInt = random.randint(0, len(list1))
randInt2 = random.randint(0, len(list2))
new_tuple += [list1[randInt], list2[randInt2]]

这是一个非常简单的python。试代码。

Answer 5

你想要的基本上是一个笛卡尔积。尝试使用itertools进行列表推导，例如:

import itertools
list1 = ["a", "b", "c"]
list2 = ["wow", 2]
new_tuple = [x for x in itertools.product(list1, list2)]

Answer 6

使用itertools.product:

from itertools import product
new_tuple = tuple([a, b] for b, a in product(list2, list1))
# (['a', 'wow'], ['b', 'wow'], ['c', 'wow'], ['a', 2], ['b', 2], ['c', 2])

Answer 7

要将2个列表转换为元组，有.zip方法:

list(zip(list1, list2))

但是它只是在你的情况下添加元素:(["a"， "哇"]， ["b"， "2"]]，所以:

a = ("John", "Charles", "Mike")
b = ("Jenny", "Christy", "Monica")

---

tuples = []
def combineTuples(listA, listB):
for i in range(len(listA)):
for j in range(len(listB)):
tuples.append((a[i], b[j]))

x = combineTuples(a, b)

print(tuples)

输出:(("约翰","珍妮")("约翰","小茉莉")("约翰","莫尼卡")("查尔斯"、"珍妮")("查尔斯"、"小茉莉")("查尔斯"、"莫尼卡")("迈克","珍妮")("迈克","小茉莉")("迈克","莫尼卡")]

输出与您的数据相同，但没有顺序。

[(' a ', '哇'),(' a ', 2),(‘b’,‘哇’),(' b ', 2), (' c ', '哇'),(' c ', 2)]