将类似的列表元素分组到字典中而不分组多次出现

Question

我有一个巨大的列表，我将其转换为字典(基于第一个列表元素)，以便快速搜索键。

列表:

[0100,A,1.00,1]
.
.
[0450,A,1.00,1]
[0470,B,1.00,1]
[0480,A,1.00,1]
[0490,A,1.00,1]
[0500,A,1.00,1] #list-1 for below ref
[0510,B,1.00,1]
[0520,A,1.00,1]
[0530,A,1.00,1]
[0500,A,1.00,1] #list-2 for below ref
[0510,B,1.00,1]
[0520,X,1.00,1] #........

转换成Dic:

for key, *vals in bytes_data: #Probably need a diff approach here itself instead appending
data_dict.setdefault(key, []).append(vals) 

字典看起来像

{
'0450': [[A,1.00,1]],
'0470': [[B,1.00,1]],
'0480': [[A,1.00,1]], #......
}

现在，我当前的场景需要像4xx/5xx/…根据情况。其中，我使用…

key_series = ["0" + str(x) for x in range(500, 600, 10)]
article_data = {
key: data_dict[key] for key in set(key_series) & set(data_dict)
}

问题是，对于某些系列，如5xx，有多次出现。在这种情况下，我的字典被分组为

{
0500: [list-1,list-2,..],
0510: [list-1,list-2,..]
}

但是，我需要像

这样的东西

{
0500-1: {0500: [list-1], 0510: [list-1],....}, 
0500-2: {0500: [list-2], 0510: [list-2],....},
}

有什么技巧可以做到这一点吗?谢谢。

Answer 1

不确定，如果这是你想要的，让我知道这是否解决了你的问题

from collections import defaultdict
data_dict = {
"0500": [["A",1.00,1]],
"0510": [["A",1.00,1], ["B",1.00,1], ["B",1.00,1]],
"0520": [["A",1.00,1], ["D",1.00,1]]
}
key_series = ["0" + str(x) for x in range(500, 600, 10)]
article_data = {
key: data_dict[key] for key in set(key_series) & set(data_dict)
}
res = defaultdict(dict)
for k ,v in data_dict.items():
for i, d in enumerate(v):
# for now 0500 is hardcoded, which can be made dynamic as per requirement
res[f"0500-{i+1}"][k] = d
print(res)