在groovy中将path中的字符串替换为另一个字符串

Question

我想替换自:

"stable_dev/201904 _xx/text1/text2.zip"
"stable_dev/201904/text5/text6.war"

为:

"stable_dev/new_value/text1/text2.zip"
"stable_dev/new_value/text5/text6.war">
我试过

arrayList.toString().replaceAll("stable_dev/"+"[0-9a-zA-Z]*"+"[^a-zA-Z0-9]*"+"[0-9a-zA-Z]*"+"/", "stable_dev/new_value/"))

Answer 1

这仅针对您的示例。我们的想法是搜索stable_dev/，然后定位到下一个/，然后用新值替换它。

def str = "stable_dev/201904_xx/text1/text2.zip"
println str.replaceAll(/stable_dev/.*?//,"stable_dev/new_value/")​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​
//Output:
//stable_dev/new_value/text1/text2.zip​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​

Answer 2

我会使用split来避免过于复杂的regexp:

def replacer = { String replacement, String val ->
def parts = val.split( /d{6}_?([a-z0-9]{2})?/ )
2 != parts.size() ? val : "${parts[ 0 ]}$replacement${parts[ 1 ]}"
}
def results = [
'aaa',
"stable_dev/201904_xx/text1/text2.zip",
"stable_dev/201904/text5/text6.war"
].collect replacer.curry( 'new_value' )
assert results == [ 'aaa', 'stable_dev/new_value/text1/text2.zip', 'stable_dev/new_value/text5/text6.war' ]