awk表示意外结果

Question

大家好，我有这个格式的文档。

id first_name last_name age address telephone item1 tax1 item2 tax2 item3 tax3

我需要这个结果

id first_name last_name age address telephone item1 tax1  
id first_name last_name age address telephone item2 tax2  
id first_name last_name age address telephone item3 tax3

使用awk

awk '{for (i=5; i<NF; i+=2) print $1, $2, $3, $4, $5, $6, $i, $(i+1)}' file.txt > file2.txt

和这个意想不到的结果

id first_name last_name age address telephone address telephone 
id first_name last_name age address telephone item1 tax1 
id first_name last_name age address telephone item2 tax2 
id first_name last_name age address telephone item3 tax3

如果你能帮助我，我会很感激的。

Answer 1

要使代码工作，您需要注意需要从哪个字段ID开始迭代。在这种情况下，它是7号场。然后，你可能会开始"分裂"。您需要的数据:

awk '{for (i=7; i<NF; i+=2) print $1, $2, $3, $4, $5, $6, $i, $(i+1)}' file.txt > file2.txt

查看在线演示:

#!/bin/bash
s='id first_name last_name age address telephone item1 tax1 item2 tax2 item3 tax3'
awk '{for (i=7; i<NF; i+=2) print $1, $2, $3, $4, $5, $6, $i, $(i+1)}' <<< "$s"

输出:

id first_name last_name age address telephone item1 tax1
id first_name last_name age address telephone item2 tax2
id first_name last_name age address telephone item3 tax3