我如何访问字典在它自己的类/上下文中定义一个方法?

Question

一个低调的例子是这个类，继承自PublishableAction(提供静态.viewController()函数以及// ...所在位置使用的其他方法):

class Action extends PublishableAction {
static actionSelector = {
buttonCommit: Symbol()
};
// This part still works as intended, accessing 'Action':
static buttonSession = Action.viewController({
perform: Action.actionSelector.buttonCommit
});
// ... but here's the issue:
// ReferenceError: Cannot access 'Action' before initialization
[Action.actionSelector.buttomCommit]() {
// ...
}
}

我已经尝试使用[this.actionSelector.buttonCommit]()和[this.constructor.actionSelector.buttonCommit]()，两者对结果没有任何影响。

如何修复ReferenceError而不必将Action.actionSelector移动到全局范围?

Answer 1

您试图实现的模式有点奇怪。但也许有一个"方法"getter和返回每个可调用的方法依赖于actionSelector?

class Action extends PublishableAction {
static actionSelector = {
buttonCommit: Symbol()
};
// This part still works as intended, accessing 'Action':
static buttonSession = Action.viewController({
perform: Action.actionSelector.buttonCommit
});
get methods() {
return {
[Action.actionSelector.buttonCommit]: function() {
//...
}
};
}
} 

可以调用(new Action()).methods[Action.actionSelector.buttonCommit]()