Java Script组合字符串/数组

Question

我需要像第一个结果一样组合string1和string2。之后，我只想要唯一的信息，没有"颜色类型信息"。如第二个结果

string1 = "Green | Green | Red | Orange | Blue | Cut | Yellow | Yellow"
string2 = "Color | Color | Color | Color | Color | Technical | Color | Color"

第一个结果:string3 = Green Color | Green Color | Red Color | Orange Color | Blue Color | Cut Technical | Yellow Color | Yellow Color

第二个结果:string4 = Green | Red | Orange | Blue | Cut | Yellow

Answer 1

你可以这样做

const string1 = 'Green | Green | Red | Orange | Blue | Cut | Yellow | Yellow'
const string2 = 'Color | Color | Color | Color | Color | Technical | Color | Color'
const [arr1, arr2] = [string1, string2].map(s => s.split(' | '))

const string3 = arr1.map((s, i) => `${s} ${arr2[i]}`).join(' | ')
const string4 = [...new Set(arr1)].join(' | ')
console.log({string3, string4})

Answer 2

const string1 = 'Green | Green | Red | Orange | Blue | Cut | Yellow | Yellow'
const string2 = 'Color | Color | Color | Color | Color | Technical | Color | Color'
const combine = (str1, str2, div = ' | ') => {
str1 = str1.split(div)
str2 = str2.split(div)

return str1.map((word, i) => `${word} ${str2[i]}`).join(div)
}
const unique = str1 => [...new Set(str1.split(' | '))].join(' | ')
const firstResult = `Green Color | Green Color | Red Color | Orange Color | Blue Color | Cut Technical | Yellow Color | Yellow Color`
const secondResult = 'Green | Red | Orange | Blue | Cut | Yellow'
console.log(firstResult === combine(string1, string2))
console.log(secondResult === unique(string1))

Answer 3

你可以这样做:

string1 = "Green | Green | Red | Orange | Blue | Cut | Yellow | Yellow"
split_text = string1.split("|")
Result = Array.from(new Set(split_text.map(x => x.trim()))).join('|')
//'Green|Red|Orange|Blue|Cut|Yellow'

Answer 4

如果string1和string2的信息长度不同

var string1 = "Green | Green | Red | Orange | Blue | Cut | Yellow | Yellow";
var string2 = "Color | Color | Color | Color | Color | Technical | Color | Color";
var firstlength=string1.split("|").length;
var secondlength=string2.split("|").length;
var maxilength=firstlength;
if(secondlength>firstlength)
maxilength=secondlength;

var string1split=string1.split("|");
var string2split=string2.split("|");

var concatstr="";
for(var i=0;i<maxilength;i++){
if(string1split.length>i){
concatstr+=string1split[i];
}
if(string2split.length>i){
concatstr+=string2split[i];
}
if(i<maxilength-1){
concatstr+="|";
}
}

console.log(concatstr);

function onlyUnique(value, index, self) {
return self.indexOf(value) === index;
}
for(var i=0;i<string1split.length;i++){
string1split[i]=string1split[i].trim();
}
var uniquecolors=string1split.filter(onlyUnique);
var uniquecolorsstring=uniquecolors.join(" | ");
console.log(uniquecolorsstring);