AJAX返回读取php函数

Question

im试图回显ajax的结果；

我的php代码是

if(isset($_POST['date']) )
{
echo "<input type='radio' id='date'/>";
}

和我的ajax代码：

$.ajax(
{
type: "POST",
url: "schedule.php",
data: {date:  dateAsString},
success: function(result) 
{
$('#res').text(result); 
// i know this is .text that's why printing text instead of html input. 
// i don't know what line of code to execute my php into html command
} 
});

如何用html语言回显php代码行以打印输入

Answer 1

更改

$('#res').text(result);

至

$('#res').html(result);