我有4个.mtx文件，正在从中读取值。其中两个在读取时运行良好，没有任何问题，并在.DAT文件中产生正确的输出。然而，最后两个是非常大的文件；代码似乎正确地从文件中读取并运行，但在从这2个文件中读取时，我没有得到任何输出和错误…甚至代码计时器也没有打印时间。非常感谢您的帮助！这是代码：
program proj2matrixC40
implicit none
integer,parameter::dp=selected_real_kind(15,307)
! Set Global Variables
real(kind=dp), allocatable::Ax(:,:),A(:,:),Iglobal(:,:)
integer::At(1,3)
integer::nnz,w,n,k,ii,ff,kk
real(kind=dp)::t1,t2
call cpu_time(t1)
open(unit=78,file="e40r5000.mtx",status='old')
read(78,*) At
close(unit=78)
nnz = At(1,3)
n = At(1,1)
k = 40
kk = 35
allocate(Ax(nnz+1,3),A(nnz,3),Iglobal(k,k))
open(unit=61,file="e40r5000.mtx",status='old')
do w=1,nnz+1
read(61,*) Ax(w,:)
end do
open (unit = 53, file = "proj2matrixC40points.dat")
do ff=1,k
do ii=1,k
Iglobal(ii,ff) = (ii/ff)*(ff/ii)
end do
end do
A(1:nnz,:) = Ax(2:nnz+1,:)
call Arno(A)
call cpu_time(t2)
print '("Time elapsed = ",f10.8," seconds")', (t2 - t1)
contains
subroutine Arno(a)
real(kind=dp), intent(in)::a(:,:)
real(kind=dp),dimension(k,k)::H
real(kind=dp),dimension(k,k+1)::u,q,qconj
real(kind=dp),dimension(k,1)::x0
integer::j,f
call random_number(x0)
q(:,1) = x0(:,1)/norm2(x0(:,1))
do f=1,k
call spmat(a,q(:,f),u(:,f))
do j=1,f
qconj(j,:) = (q(:,j))
H(j,f) = dot_product(qconj(j,:),u(:,f))
u(:,f) = u(:,f) - H(j,f)*q(:,j)
end do
if (f.lt.k) then
H(f+1,f) = norm2(u(:,f))
if (H(f+1,f)==0) then
print *, "Matrix is reducible"
stop
end if
q(:,f+1) = u(:,f)/H(f+1,f)
end if
if (f==k) then
call qrit(H)
end if
end do
end subroutine
! QR Iteration with Shifts Subroutine
subroutine qrit(a)
real(kind=dp), intent(in)::a(:,:)
real(kind=dp)::sigmak
real(kind=dp),dimension(kk,k)::dia
real(kind=dp),dimension(k,k)::Qfinal,Rfinal,HH
real(kind=dp),dimension(k,k,kk)::H0,needQR
integer::v,z
HH = a
H0(:,:,1) = HH
do v=1,kk
sigmak = H0(k,k,v)
if (v-1==0) then
needQR(:,:,v) = HH - sigmak*Iglobal
else
needQR(:,:,v) = H0(:,:,v-1) - sigmak*Iglobal
end if
call givens2(needQR(:,:,v),Rfinal,Qfinal)
H0(:,:,v) = matmul(Rfinal,Qfinal) + sigmak*Iglobal
do z = 1,k
dia(v,z) = H0(z,z,v)
write(53,*) v," ", dia(v,z) ! Write values to .DAT file
end do
end do
end subroutine
! Sparse Matrix Vector Multiplication Subroutine
subroutine spmat(a,b,c)
real(kind=dp), intent(in)::a(:,:)
real(kind=dp), intent(in), dimension(k,1)::b
real(kind=dp), intent(out), dimension(k,1)::c
integer::m,rowi,columni
real(kind=dp), dimension(k,1)::x,y
x = b
y(:,1) = 0
do m = 1,nnz
rowi = a(m,1)
columni = a(m,2)
y(rowi,1) = y(rowi,1) + a(m,3)*x(columni,1)
end do
c(:,1) = y(:,1)
end subroutine
! QR Factorization Givens Rotations Subroutine
subroutine givens2(a,Rfinal,Qfinal)
real(kind=dp), intent(in)::a(:,:)
real(kind=dp), dimension(k,k,(k*k))::G,QQ
real(kind=dp), dimension(k,k), intent(out)::Rfinal,Qfinal
real(kind=dp), dimension(k,k)::I2,y,aa
real(kind=dp), dimension(1,k)::ek1,ek2
real(kind=dp)::c,s
integer::kt,m,nn,j,i,l,p
m = size(a,1)
nn = size(a,2)
aa = a
i = 1
do kt=1,nn-1
do j=m,kt+1,-1
if (aa(j,kt).eq.0) then
continue
else
ek1(1,:) = 0
ek2(1,:) = 0
do p=1,m
do l=1,m
I2(l,p) = (l/p)*(p/l)
end do
end do
c = aa(kt,kt)/sqrt(aa(kt,kt)**2 + aa(j,kt)**2)
s = aa(j,kt)/sqrt(aa(kt,kt)**2 + aa(j,kt)**2)
ek1(1,kt) = c
ek1(1,j) = s
ek2(1,kt) = -s
ek2(1,j) = c
I2(kt,:) = ek1(1,:)
I2(j,:) = ek2(1,:)
G(:,:,i) = I2
if (i.eq.1) then
QQ(:,:,i) = G(:,:,i)
else
QQ(:,:,i) = matmul(G(:,:,i),QQ(:,:,i-1))
end if
y = matmul(G(:,:,i),aa)
aa = y
if (kt.eq.nn-1) then
if (j.eq.kt+1) then
Qfinal = transpose(QQ(:,:,i))
Rfinal = aa
end if
end if
i = i + 1
end if
end do
end do
end subroutine
end program proj2matrixC40
几张纸条。我在call mat_print('H',H)周围加了星号的那一行(对于这个问题(不能删除，否则我会得到错误的答案(这很奇怪…想法？(。此外，为了让你的计算机不会冻结打开大文件，它们的名称是"e40r5000.mtx"one_answers"s3dkt3m2.mtx"(这两个我有问题(。我使用的是gfortran版本8.1.0
这是文件的链接
https://1drv.ms/f/s！AjG0dE43DVddaJfY62ABE8Yq3CI
当您需要添加一个调用到一个实际上不应该更改任何内容的子例程以使事情正常工作时，您可能会出现内存损坏。当您访问数组边界之外的数组时，这种情况最常见。
我用一些运行时检查编译了它：
gfortran -o p2m -g -O0 -fbacktrace -fcheck=all -Wall proj2mat.f90
它已经给我带来了一些问题：
- 它警告我有关隐式类型转换的问题。如果你相信自己的数据，这应该不会成为太大的问题
- 在第46行中，数组长度不匹配(
x0(:, 1)的长度为40，q(:,1)的长度为41( - 类似地，在108线上(
x=b(x确实很大，但b只有41长
我现在已经停止了，但我恳请您仔细检查您的代码并清理它。使用上面的编译器选项，可以让您知道何时何地存在数组绑定冲突。