删除重复的行，按最大值(日期时间)保留最近的行

Question

下面的MySQL语句根据ADDRESS1和POSTCODE选择所有重复的行，其中最近的一行INSPECTION_DATE。从本质上讲，它选择了我想要保留的所有内容。

SELECT COUNT(*), MAX(INSPECTION_DATE), ADDRESS1, POSTCODE, id
FROM epc 
GROUP BY ADDRESS1, POSTCODE 
HAVING COUNT(*) > 1;

我的问题是，如何删除所有旧的重复项，保留上面语句返回的重复项。

Answer 1

http://sqlfiddle.com/#！9/8de866/1

DELETE  e
FROM epc e
INNER JOIN epc max_
ON e.address1 = max_.address1
AND e.postcode = max_.postcode
AND e.inspection_date < max_.inspection_date;

更新http://sqlfiddle.com/#！9/5bd5981/1

DELETE  e
FROM epc e
INNER JOIN epc max_
ON e.address1 = max_.address1
AND e.postcode = max_.postcode
AND (e.inspection_date < max_.inspection_date
OR (e.inspection_date = max_.inspection_date
AND e.id < max_.id));