使用XSLT删除第二个元素的重复节点

Question

我对xslt没有太多知识。我试图从我的输入xml中删除一些重复的节点，但这些节点并不完全重复。PremiseId值重复，但纬度、经度、XCordinate和YCordinate值不同。如果我们在Input xml中得到这样的数据，那么我们只需要选择出现的具有纬度、经度值的xml节点。目前，我的xslt只接收到第一次出现重复的PremiseId。

输入XML:-

<CoordinateCollectionRes
xmlns="http://www.nexteraenergy.org/RetrieveCoordinateResponseSchema"
xmlns:soap-env="http://schemas.xmlsoap.org/soap/envelope/">
<ResponseParameter>
<PremiseId>42210111</PremiseId>
<Latitude>-80.81082</Latitude>
<Longitude>28.58942</Longitude>
<Xcoordinate>3913026</Xcoordinate>
<Ycoordinate>-42817728</Ycoordinate>
</ResponseParameter>
<ResponseParameter>
<PremiseId>59087449</PremiseId>
<Latitude/>
<Longitude/>
<Xcoordinate>0.0</Xcoordinate>
<Ycoordinate>0.0</Ycoordinate>
</ResponseParameter>
<ResponseParameter>
<PremiseId>60476616</PremiseId>
<Latitude/>
<Longitude/>
<Xcoordinate>0.0</Xcoordinate>
<Ycoordinate>0.0</Ycoordinate>
</ResponseParameter>
<ResponseParameter>
<PremiseId>60476616</PremiseId>
<Latitude>-87.36536</Latitude>
<Longitude>30.391645</Longitude>
<Xcoordinate>1556955</Xcoordinate>
<Ycoordinate>-41998772</Ycoordinate>
</ResponseParameter>
</CoordinateCollectionRes>

XSLT:-

<?xml version="1.0" encoding="windows-1252" ?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ns1="http://www.nexteraenergy.org/RetrieveCoordinateResponseSchema">
<xsl:template match="/">
<CoordinateCollectionRes xmlns="http://www.nexteraenergy.org/RetrieveCoordinateResponseSchema">
<xsl:for-each-group select="/ns1:CoordinateCollectionRes/ns1:ResponseParameter" group-by="./ns1:PremiseId">
<xsl:copy-of select=".[./ns1:PremiseId=current-grouping-key()]"/>
</xsl:for-each-group>
</CoordinateCollectionRes>
</xsl:template>
</xsl:stylesheet>

输出XML:-

<CoordinateCollectionRes    xmlns:ns1="http://www.nexteraenergy.org/RetrieveCoordinateResponseSchema" xmlns="http://www.nexteraenergy.org/RetrieveCoordinateResponseSchema">
<ResponseParameter>
<PremiseId>42210111</PremiseId>
<Latitude>-80.81082</Latitude>
<Longitude>28.58942</Longitude>
<Xcoordinate>3913026</Xcoordinate>
<Ycoordinate>-42817728</Ycoordinate>
</ResponseParameter>
<ResponseParameter>
<PremiseId>59087449</PremiseId>
<Latitude/>
<Longitude/>
<Xcoordinate>0.0</Xcoordinate>
<Ycoordinate>0.0</Ycoordinate>
</ResponseParameter>
<ResponseParameter>
<PremiseId>60476616</PremiseId>
<Latitude/>
<Longitude/>
<Xcoordinate>0.0</Xcoordinate>
<Ycoordinate>0.0</Ycoordinate>
</ResponseParameter>
</CoordinateCollectionRes>

预期输出XML:-

<CoordinateCollectionRes    xmlns:ns1="http://www.nexteraenergy.org/RetrieveCoordinateResponseSchema" xmlns="http://www.nexteraenergy.org/RetrieveCoordinateResponseSchema">
<ResponseParameter>
<PremiseId>42210111</PremiseId>
<Latitude>-80.81082</Latitude>
<Longitude>28.58942</Longitude>
<Xcoordinate>3913026</Xcoordinate>
<Ycoordinate>-42817728</Ycoordinate>
</ResponseParameter>
<ResponseParameter>
<PremiseId>59087449</PremiseId>
<Latitude/>
<Longitude/>
<Xcoordinate>0.0</Xcoordinate>
<Ycoordinate>0.0</Ycoordinate>
</ResponseParameter>
<ResponseParameter>
<PremiseId>60476616</PremiseId>
<Latitude>-87.36536</Latitude>
<Longitude>30.391645</Longitude>
<Xcoordinate>1556955</Xcoordinate>
<Ycoordinate>-41998772</Ycoordinate>
</ResponseParameter>
</CoordinateCollectionRes>

Answer 1

怎么样：

XSLT 2.0

<xsl:stylesheet version="2.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns="http://www.nexteraenergy.org/RetrieveCoordinateResponseSchema"
xpath-default-namespace="http://www.nexteraenergy.org/RetrieveCoordinateResponseSchema">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/CoordinateCollectionRes">
<CoordinateCollectionRes>
<xsl:for-each-group select="ResponseParameter" group-by="PremiseId">
<xsl:copy-of select="(current-group()[string(Latitude|Latitutde)], current-group())[1]" copy-namespaces="no"/>
</xsl:for-each-group>
</CoordinateCollectionRes>
</xsl:template>
</xsl:stylesheet>

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演示：https://xsltfiddle.liberty-development.net/93dFepY