我有一个有序的元组(它的2维，第0列是我的结尾，我想比较它&第1列是完整的url(，在"列"；[0]我必须比较第一个值和第二个值，如果它们相同，则将第一个值保存到其他列表中并重复。我想把每一个项目与下面的项目进行比较，无论它们是否真的。
元组：
[('https://www.topart-online.com/de/Rose%2C-Micle%2C-kupfer%2C-52cm%2C-Oe-9cm/c-KAT240/a-XH0124KP', '/a-XH0124KP'), ('https://www.topart-online.com/de/Rose%2C-Micle%2C-kupfer%2C-52cm%2C-Oe-9cm/c-KAT183/a-XH0124KP', '/a-XH0124KP'), ('https://www.topart-online.com/de/Rose%2C-Micle%2C-kupfer%2C-52cm%2C-Oe-9cm/c-KAT173/a-XH0124KP', '/a-XH0124KP'), ('https://www.topart-online.com/de/Liguster-Zweig-50cm-mit-Glitter/c-KAT184/a-XM0721', '/a-XM0721'), ('https://www.topart-online.com/de/3D-Stern-schwarz-mit-Glitter%2C-7%2C5-cm---SUPER-DEAL/c-KAT14/a-XM1633ZW', '/a-XM1633ZW'), ('https://www.topart-online.com/de/Christbaumschmuck%2C-Zweige%2C-gold-30-cm----SUPER-DEAL/c-KAT14/a-XP0091', '/a-XP0091')]
我想比较从url中提取的产品编号，因为每个产品都可能在多个url中找到
我的分类尝试：
sized = len(complete_links2) - 1
for index, tuple in enumerate(complete_links2):
index = k
k = index + 1
if k < sized:
while complete_links2[index][1] == complete_links2[k][1]:
k += 1
if complete_links2[index][1] == complete_links2[k][1]:
k -= 1
not_rep_links.append(complete_links2[index])
complete_links3 = [a_tuple[0] for a_tuple in not_rep_links]
我的问题是，有一些独特的链接，也会被过滤掉，因为我的逻辑不是很好。
我还尝试了set，打开元组，但我不知道如何继续
我还是有点困惑，但这是你想要的吗？
list_ = [
('https://www.topart-online.com/de/Rose%2C-Micle%2C-kupfer%2C-52cm%2C-Oe-9cm/c-KAT240/a-XH0124KP', '/a-XH0124KP'),
('https://www.topart-online.com/de/Rose%2C-Micle%2C-kupfer%2C-52cm%2C-Oe-9cm/c-KAT183/a-XH0124KP', '/a-XH0124KP'),
('https://www.topart-online.com/de/Rose%2C-Micle%2C-kupfer%2C-52cm%2C-Oe-9cm/c-KAT173/a-XH0124KP', '/a-XH0124KP'),
('https://www.topart-online.com/de/Liguster-Zweig-50cm-mit-Glitter/c-KAT184/a-XM0721', '/a-XM0721'),
('https://www.topart-online.com/de/3D-Stern-schwarz-mit-Glitter%2C-7%2C5-cm---SUPER-DEAL/c-KAT14/a-XM1633ZW', '/a-XM1633ZW'),
('https://www.topart-online.com/de/Christbaumschmuck%2C-Zweige%2C-gold-30-cm----SUPER-DEAL/c-KAT14/a-XP0091', '/a-XP0091')
]
products = []
links = []
for item in list_:
if item[1] not in products:
products.append(item[1])
links.append(item[0])
print(links)