从windows批处理中的文件名字符串中获取变量

Question

你好，我有一个文件夹，里面有400个文件，我想打印一个"name"；从文件名这就是结构ej:

20201323223_vendo.perfil01_17872513294967257_1601950878_live.mp4
20201323223__vvcastrillon_12_17949951031375250_1601939874_live.mp4
2020323123_yessromero.g_17849208194340047_1601945592_live.mp4
2020323223_ziizii_08_17979840166310477_1601929868_live.mp4

我需要的是

vendo.perfil01
_vvcastrillon_12
yessromero.g
ziizii_08

我试图在文件中循环并分离_，并提取2和3标记数字条件，但结果是错误的，缺少变量

@echo off
setlocal EnableDelayedExpansion
:loop
SET max=5000
for /F "delims=" %%I in ('dir "*_*_*.mp4" /A-D /B /S 2^>nul ^| %SystemRoot%System32findstr.exe /I /L /V "\outdir\"') do (for /F "eol=| tokens=2,3 delims=_" %%J in ("%%~nI") do (SET "var="&for /f "delims=0123456789" %%a in ("%%K") do SET var=%%a
if defined var ( set nam=%%J_%%K ) else ( set nam=%%J )
)
echo/!nam!
)
timeout 10 > nul
goto loop

我认为答案是删除_之前的第一个数字，然后删除末尾的字符串_xxxxxx_xxxxxxx_live.mp4，但我不知道如何反向读取令牌

储罐的任何帮助

Answer 1

由于文件名中甚至相邻的_中有不同数量的_分隔项，因此使用for /F将它们拆分为具有delims=_的特定令牌不是最佳选择。

我将使用标准的for循环，它接收修改后的文件名，即每个_都被" "替换并包含在""中，这导致SPACE分隔的部分名称项。因此：

20201323223_vendo.perfil01_17872513294967257_1601950878_live.mp4

更改为：

"20201323223" "vendo.perfil01" "17872513294967257" "1601950878" "live.mp4"

循环之前。在循环中实现一个索引计数器，并将这些项附加到一个缓冲区，该缓冲区的索引号位于某个范围内，该范围取决于项的总数。

下面是一个示例脚本，演示了我的意思：

@echo off
setlocal EnableExtensions DisableDelayedExpansion
rem // Define constants here:
set "_ROOT=%~dp0."           & rem // (full path to target directory)
set "_MASK=*_*_*_*_live.mp4" & rem // (pattern to match file names)
set "_FILT=^[0123456789][0123456789]*_..*_[0123456789][0123456789]*_[0123456789][0123456789]*_live.mp4$"
rem // (additional `findstr` filter for file names)
set /A "_POS=1"              & rem /* (index of first `_`-separated item to extract;
rem     `0` is the first item, `-1` is the last) */
set /A "_NUM=-4"             & rem /* (number of `_`-separated items to extract;
rem     `-1` means all up to the last item) */
rem // Change into target directory:
pushd "%_ROOT%" && (
rem // Loop through all matching non-hidden, non-system files:
for /F "delims= eol=|" %%F in ('
dir /B /A:-D-H-S "%_MASK%" ^| findstr /I /R /C:"%_FILT%"
') do (
rem // Store current file name, initialise item index, counter and buffer:
set "FILE=%%F" & set /A "IDX=-1, CNT=-1" & set "BUFF=_"
rem // Toggle delayed expansion to avoid troubles with `!`:
setlocal EnableDelayedExpansion
rem // Count number of items and store one less:
rem set "TEST=%FILE:_=" & set /A "CNT+=1" & set "TEST=%"
for %%I in ("!FILE:_=" "!") do set /A "CNT+=1"
rem // Determine item index position from given index and number:
if !_POS! lss 0 (set /A "BEG=CNT+_POS+1") else set /A "BEG=_POS"
if !_NUM! lss 0 (set /A "END=CNT+_NUM+1") else set /A "END=_POS+_NUM-1"
rem // Transport numbers over `endlocal` barrier:
for %%C in (!CNT!) do for %%B in (!BEG!) do for %%A in (!END!) do (
rem // Loop through `_`-separated items of file name:
for %%I in ("!FILE:_=" "!") do (
rem // Store current item, increment item index:
endlocal & set "ITEM=%%~I" & set /A "IDX+=1"
setlocal EnableDelayedExpansion
rem // Append current item to buffer if in range:
if !IDX! geq %%B if !IDX! leq %%A (
rem // Transport buffer over `endlocal` barrier:
for /F "delims=" %%E in ("BUFF=!BUFF!_!ITEM!") do (
endlocal & set "%%E"
setlocal EnableDelayedExpansion
)
)
)
)
rem // Return buffer:
echo(!BUFF:~2!
endlocal
)
rem // Return from target directory:
popd
)
endlocal
exit /B

Answer 2

这样的东西应该会有所帮助：

@echo off
setlocal enabledelayedexpansion
for /f "tokens=1* delims=_." %%i in ('dir /b /s /a-d "*_*_*.mp4"2^>nul ^| findstr.exe /ILV "\outdir\"') do (
set "var=%%j"
for /f "tokens=2,* delims=_." %%a in ("%%j") do echo !var:_%%b=!
)

请记住，使用delims也会拆分双下划线等连续字符。对于那些需要预先确定哪一个有双下划线并让脚本为您添加下划线的人。

Answer 3

@ECHO OFF
SETLOCAL
for %%a in (
20201323223_vendo.perfil01_17872513294967257_1601950878_live.mp4
20201323223__vvcastrillon_12_17949951031375250_1601939874_live.mp4
2020323123_yessromero.g_17849208194340047_1601945592_live.mp4
2020323223_ziizii_08_17979840166310477_1601929868_live.mp4
) do  set "filename=%%a" &call :process&echo --------------------------------------
GOTO :EOF
:process
echo stage 1 %filename%
:: step 1 : delete all characters up to and including the first underscore
set "filename=%filename:*_=%"
echo stage 2 %filename%
:: step 2 : find all numeric strings of length 4 or more in remainder
call :strsgt4 %filename:_= %
:: step 3 : replace each numeric string of length 4 or more + preceding underscore with "/" (invalid filename character)
echo stage 3 %filename%
:proc3lp
if "%zapstrings%" neq " " for %%v in (%zapstrings%) do call set "filename=%%filename:_%%v=/%%"&call set "zapstrings=%%zapstrings: %%v=%%"&goto proc3lp 
echo stage 4 %filename%
:: step 5 : Remove all charactersincluding and after the first "/"
for /f "delims=/" %%v in ("%filename%") do echo result %%v
goto :eof
:strsgt4
set "zapstrings= "
:strsgt4loop
set "test=%1"
if not defined test goto :eof
set "test=%test:~4%"
if defined test call :isnum %test%&if not defined notnumber set "zapstrings=%zapstrings% %1"
shift
goto strsgt4loop
:: Determine whether %1 is purely numeric
:isnum
SET "notnumber=9%~1"
FOR /l %%z IN (0,1,9) DO CALL SET "notnumber=%%notnumber:%%z=%%"
GOTO :eof

真正的问题是弄清楚你的规则是什么。

我决定你的规则是：第一个下划线之后的字符串，直到数字字符串或长度大于3 的第一个后续下划线之前

%%a循环简单地向:process提交一个样本字符串序列

内联注释应该解释其余部分。