UEFI c++:使用Print时，会发生wchar_t转换错误

Question

我想尝试在c++中制作一个小的(U(EFI引导程序，但是，当我尝试编译我的代码(使用g++(时，会出现以下错误：

boot.cpp: In function ‘EFI_STATUS efi_main(EFI_HANDLE, EFI_SYSTEM_TABLE*)’:
boot.cpp:9:9: error: invalid conversion from ‘const wchar_t*’ to ‘const CHAR16*’ {aka ‘const short unsigned int*’} [-fpermissive]
9 |   Print(L"Hello, world!n");
|         ^~~~~~~~~~~~~~~~~~
|         |
|         const wchar_t*
In file included from boot.cpp:2:
/usr/include/efi/efilib.h:504:24: note:   initializing argument 1 of ‘UINTN Print(const CHAR16*, ...)’
504 |     IN CONST CHAR16   *fmt,

我使用了这个命令(我在Ubuntu WSL2上工作(：

g++ boot.cpp -mno-red-zone -ffreestanding -fshort-wchar -nostdlib -e efi_main -Wl,-dll -shared -Wl,--subsystem,10 -c -I/usr/include/efi/ -I/usr/include/efi/x86_64/

这是我的代码：

#include <efi.h>
#include <efilib.h>
EFI_STATUS
EFIAPI
efi_main (EFI_HANDLE ImageHandle, EFI_SYSTEM_TABLE *SystemTable)
{
InitializeLib(ImageHandle, SystemTable);
Print(L"Hello, world!n");
return EFI_SUCCESS;
}

编辑：如果我从"；你好，世界；，给我这个错误：

boot.cpp: In function ‘EFI_STATUS efi_main(EFI_HANDLE, EFI_SYSTEM_TABLE*)’:
boot.cpp:9:9: error: cannot convert ‘const char*’ to ‘const CHAR16*’ {aka ‘const short unsigned int*’}
9 |   Print("Hello, world!n");
|         ^~~~~~~~~~~~~~~~~
|         |
|         const char*
In file included from boot.cpp:2:
/usr/include/efi/efilib.h:504:24: note:   initializing argument 1 of ‘UINTN Print(const CHAR16*, ...)’
504 |     IN CONST CHAR16   *fmt,

编辑2:如果我在hello world(u"hello，world\n&"(前面使用u，则会出现以下错误：

boot.cpp: In function ‘EFI_STATUS efi_main(EFI_HANDLE, EFI_SYSTEM_TABLE*)’:
boot.cpp:9:9: error: invalid conversion from ‘const char16_t*’ to ‘const CHAR16*’ {aka ‘const short unsigned int*’} [-fpermissive]
9 |   Print(u"Hello, world!n");
|         ^~~~~~~~~~~~~~~~~~
|         |
|         const char16_t*
In file included from boot.cpp:2:
/usr/include/efi/efilib.h:504:24: note:   initializing argument 1 of ‘UINTN Print(const CHAR16*, ...)’
504 |     IN CONST CHAR16   *fmt,

Answer 1

I解析，使用gcc而不是g++，并强制转换为CHAR16*