我目前正在进行一个angular项目，将我们现有的应用程序从jsp更新到angular 7。然而，有些jsp页面我还不能完全转换为html，因为它们需要遗留的支持。
所以我需要知道如何将它们移动到角度。我的想法是将jsp页面及其所有css复制到angular组件。
The jsp code is something like below
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<%@ include file="/WEB-INF/jsp/cwf/common/include.jsp"%>
<link
href="<%=request.getContextPath()%>/static/css/insurance/insureServ.css"
rel="stylesheet" type="text/css" />
<%-- START CONTAINER --%>
<div id="container">
<%-- START HEADER --%>
<div id="header">
<div class="headerLogoProd"> </div>
<%-- ///Use class="headerLogoPSE" or class="headerLogoProd" depending on desired logo /// --%>
<div class="floatleft">
Welcome,
<c:out default="Guest" value="${name}" />
</div>
<div
style="border-style: none; float: left; font-size: 1.5em; font-family: sans-serif; color: #FF800D">PRODUCTION</div>
<div class="floatright">
<a target="_blank"
href="http://test.net">Contact
Us</a> | <a href="mailto:insurance@tst.net">Feedback</a> | <a
target="_blank" href="http://fakeurl.net">ABDHome</a>
</div>
<%-- START Icon Elements --%>
<c:forEach items="${userTamRoles}" var="userTamRole">
<c:if test="${userTamRole eq 'ATH'}">
<div class="icon_element"
onMouseOver="this.className='icon_elementHover'"
onMouseOut="this.className='icon_element'">
<a target="_blank" href="fake.do"><img
src="static/images/ins/asdf.gif" alt=""
width="90" height="70" vspace="5" align="left"><br />
<h3>Inquiry</h3> View transactions for the
Transfer Service.</a>
</div>
</c:if>
///More html code similar to above here
</div>
<%-- END CONTAINER --%>
<script type="text/javascript">
var url = window.location.href;
var n = url.indexOf("https://pott");
if(n > -1) {
document.getElementById("ddd").style.display = "none";
}
</script>
现在，使用spring的当前代码具有如下所示的Web erivce
@RequestMapping(value = "/inland", method = RequestMethod.GET)
public ModelAndView insuranceLandingpage(HttpServletRequest request) throws Exception {
// get the user name and set it in the session, we will use this in the jsp
String name = cuoUser.getUserFirstName() + " " + cuoUser.getUserLastName();
request.getSession().setAttribute("name", name);
// get entitled products /Roles from TAM
List<String> user= this.headerUtil.getRolesFromReqHeader(request, userId);
request.setAttribute("userTamRoles", user);
return new ModelAndView(".abc.portal.insurance");
}
servlet.xml具有映射定义的
**
<definition name=".abc.portal.insurance"
template="/WEB-INF/jsp/tiles/insurance/inlanding.jsp">
<put-attribute name="body"
value="/WEB-INF/jsp/tiles/insurance/inlanding.jsp" />
**
现在使用angular，我不能使用模型和视图，所以我必须重构webservice以返回json对象。但是，如何呈现jsp页面？我可以复制整个jsp页面，并将其粘贴到angular中的一个组件中。但是如何呈现请求参数呢？E.g，我该如何渲染<c:forEach items="${userTamRoles}" var="userTamRole"> or <c:out default="Guest" value="${name}" />进入角分量？它会将其识别为jsp语法吗？
我自己解决了这个问题。我只是在servlet xml文件中添加了一个视图解析器，而不是在angular上重新呈现jsp页面。
<bean id="viewResolver"
class="org.springframework.web.servlet.view.UrlBasedViewResolver">
<property name="viewClass">
<value>org.springframework.web.servlet.view.tiles2.TilesView</value>
</property>
</bean>
<bean id="tilesConfigurer"
class="org.springframework.web.servlet.view.tiles2.TilesConfigurer">
<property name="definitions">
<list>
<value>/WEB-INF/config/spring-tiles.xml</value>
<!-- <value>/WEB-INF/config/cwf/tiles-defs-cwf.xml</value> -->
</list>
</property>
</bean>