MySQL所说的"Column count doesn't match value count at row 1"是什么意思



这是我得到的消息

ER_WRONG_VALUE_COUNT_ON_ROW:列计数与第1行的值计数不匹配

这是我的全部代码。我的错误在哪里?

DROP TABLE student;
CREATE TABLE employee (
emp_id INT PRIMARY KEY,
first-name VARCHAR(40),
birth_day DATE,
sex VARCHAR(1),
SALARY INT,
super_id INT,
branch_id INT
);
CREATE TABLE branch (
branch_id INT PRIMARY KEY,
branch_name VARCHAR(40),
mgr_id INT,
mgr_start_date DATE,
FOREIGN KEY(mgr_id) REFERENCES employee(emp_id) ON DELETE SET NULL
);
CREATE TABLE works_with (
emp_id INT,
client_id INT,
total_sales INT,
PRIMARY KEY(emp_id, client_id),
FOREIGN KEY(emp_id) REFERENCES employee(emp_id) ON DELETE CASCADE,
FOREIGN KEY(client_id) REFERENCES client(client_id) ON DELETE CASCADE
);
-- Corporate
INSERT INTO employee VALUES(100, 'David', 'Wallace', '1967-11-17', 'M', 250000, NULL, NULL);
INSERT INTO branch VALUES(1, 'Corporate', 100, '2006-02-09');
UPDATE employee
SET branch_id = 1
WHERE employee_id = 100;
INSERT INTO employee VALUES(101, 'Jan', 'Levinson', '1961-05-11', 'F', 110000, 100, 1);

您的employee表有7列,但您为insert提供了8个值,这将生成您得到的错误消息。

一个好习惯是在语句中列出insert的列。这使得这种类型的错误更容易发现,因为您不需要回顾表的定义(如果您在将来向表中添加新列或删除现有列,这也可以防止查询失败(。

INSERT INTO employee(emp_id, first_name, birth_day, sex, salary, super_id, branch_id)
VALUES(100, 'David', 'Wallace', '1967-11-17', 'M', 250000, NULL);

旁注:可以在employeecreate table语句中看到的未引用标识符first-name无效,因为它包含短划线(-(。我认为这是一个拼写错误,而您的意思是下划线(first_name(。

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