将TouchEvent从一个视图转移到另一个视图

Question

我使用的是Android键盘和长按键盘键后打开的弹出窗口。我想直接将MotionEvent DOWN从键盘转移到PopupWindow，这样用户就不必执行Action UP和再次执行DOWN来点击popupkeyboard。

这就是我在OnLongPress:中所做的

@Override
protected boolean onLongPress(AppKeyboard.Key popupKey) {
showPopup(popupKey);
return true;
}
public void showPopup(AppKeyboard.Key popupKey) {
ContextThemeWrapper ctx = new ContextThemeWrapper(context, R.style.AppTheme);
LayoutInflater inflater = LayoutInflater.from(ctx);
View popupView = inflater.inflate(R.layout.popup_layout, null);
FontsKeyboardView keyboardView = popupView.findViewById(R.id.popup_keyboard_view);
keyboardView.setClipToOutline(true);
AppKeyboard keyboard = new AppKeyboard(context, R.xml.popup_test);
keyboardView.setKeyboard(keyboard);
popupWindow = new PopupWindow(ctx);
popupWindow.setContentView(popupView);
popupWindow.setAttachedInDecor(false);
popupWindow.setOutsideTouchable(true);
getLocationInWindow(this.windowOffset);
int i = this.windowOffset[0] + popupKey.x;
popupView.measure(MeasureSpec.makeMeasureSpec(getWidth(), MeasureSpec.AT_MOST),
MeasureSpec.makeMeasureSpec(getHeight(), MeasureSpec.AT_MOST));
measuredHeight=popupView.getMeasuredHeight();
int heightoffset= (this.windowOffset[1] + popupKey.y) - measuredHeight;
Toast.makeText(context, String.valueOf(measuredHeight), Toast.LENGTH_SHORT).show();
popupWindow.showAtLocation(this, 0, i, heightoffset);
}

@Override
public boolean onTouchEvent(MotionEvent motionEvent) {
if (this.popupWindow != null) {
Toast.makeText(context, "Executed", Toast.LENGTH_SHORT).show();
if (motionEvent.getAction() == MotionEvent.ACTION_POINTER_UP || motionEvent.getAction() == MotionEvent.ACTION_UP) {
motionEvent = translateToPopupCoordinates(motionEvent, 1);
motionEvent.recycle();
PopupWindow popupWindow2 = this.popupWindow;
this.popupWindow = (PopupWindow) null;
popupWindow2.dismiss();
return true;
} else if (motionEvent.getAction() == MotionEvent.ACTION_MOVE) {
View contentView = popupWindow.getContentView();
if (!contentView.isAttachedToWindow()) {
return true;
}
motionEvent = translateToPopupCoordinates(motionEvent, 0);
popupWindow.getContentView().onTouchEvent(motionEvent);
motionEvent.recycle();
return true;
}
}
return super.onTouchEvent(motionEvent);
}
private final MotionEvent translateToPopupCoordinates(MotionEvent motionEvent, int i) {
long downTime = motionEvent.getDownTime();
long eventTime = motionEvent.getEventTime();
float x = ((float) this.windowOffset[0]) + (motionEvent.getX() - ((float) this.windowPopupOffset[0]));
float y = (motionEvent.getY() - ((float) this.windowPopupOffset[1])) + ((float) this.windowOffset[1]);
PopupWindow popupWindow = this.popupWindow;
View contentView = popupWindow.getContentView();
motionEvent = MotionEvent.obtain(downTime, eventTime, i, x, Math.min(y, ((float) contentView.getHeight()) - ((float) 1)), motionEvent.getMetaState());
return motionEvent;
}

Answer 1

onLongPress返回一个boolean，它表示事件是由该方法处理还是应该进一步传播。如果你返回true，你基本上是在说"我已经处理了这个事件，不需要再传播了"；。因此，您实际上可以将false传递到那里，然后事件将传递到队列中的下一个View以处理该事件。你可能需要稍微调整一下，让它为你的用例工作。