将views.py拆分为模块时出现未定义的变量错误-Django

Question

我在views.py中的代码一天比一天大，现在我想把它拆分成模块。但我在变量方面遇到了麻烦。问题在于，我不知道应该在哪里声明变量或导入内置模块：在我的自定义模块或views.py中。这是我的代码：

views.py:

@login_required(login_url='sign_in')
def result(request):
find_by_fives()
context = {
'last_uploaded': last_uploaded,
'words_count': words_count,
'characters_count': characters_count
}
return render(request, 'result.html', context)

find_by_fives.py(是我的自定义模块(：

import glob 
from .models import OriginalDocument
from django.shortcuts import render
def find_by_fives():
last_uploaded = OriginalDocument.objects.latest('id')
original = open(str(last_uploaded.document), 'r')
original_words = original.read().lower().split()
words_count = len(original_words)
open_original = open(str(last_uploaded.document), "r")
read_original = open_original.read()
characters_count = len(read_original)
path = 'static/other_documents/doc*.txt'
files = glob.glob(path)                       

错误：NameError: name 'last_uploaded' is not defined

注意：这不是我的全部视图，我只想知道应该在哪里声明context、变量和导入。

Answer 1

好的，我明白了-"find_by_fives.py"是一个函数，对吧？所以你在里面声明的变量只存在于那里。因此，当你从views.py调用这个函数时，它们会被声明，然后，当函数结束时，它们就会被删除。如果你想在views.py中使用它们，你应该返回它们并在那里分配一个变量，然后将它们传递到上下文：

@login_required(login_url='sign_in')
def result(request):
last_uploaded, words_count, characters_count = find_by_fives()
context = {
'last_uploaded': last_uploaded,
'words_count': words_count,
'characters_count': characters_count
}
return render(request, 'result.html', context)
def find_by_fives():
last_uploaded = OriginalDocument.objects.latest('id')
original = open(str(last_uploaded.document), 'r')
original_words = original.read().lower().split()
words_count = len(original_words)
open_original = open(str(last_uploaded.document), "r")
read_original = open_original.read()
characters_count = len(read_original)
path = 'static/other_documents/doc*.txt'
files = glob.glob(path) 
return last_uploaded, words_count, characters_count