如何使用RestTemplate在List中获取结果并将响应放入List

Question

嗨，我试图实现的是，我想使用其他API，并使用RestTemplate将一些响应数据放入我的函数中的List中，下面是我的代码的样子：

@PostMapping("/save-new")
public ResponseEntity<ShipmentAddressGrouping> saveNewShipmentAddressGrouping(@Valid @RequestBody InputRequest<ShipmentAddressGroupingDto> request) {
String url = baseUrl + "/load-list";
HttpEntity<PartnerShipmentDto> requestPartnerShipmentDto = new HttpEntity<>(new PartnerShipmentDto());
RestTemplate restTemplate = new RestTemplate();
List<PartnerShipmentDto> partnerShipmentDto = restTemplate.postForObject(url, requestPartnerShipmentDto, new ParameterizedTypeReference<List<PartnerShipmentDto>>() {});
ShipmentAddressGrouping newShipmentAddressGrouping = shipmentAddressGroupingService.save(request);
return ResponseEntity.ok(newShipmentAddressGrouping);
}

正如你所看到的，我试图在列表中获得响应，也就是我在这里尝试restTemplate.postForObject(url, requestPartnerShipmentDto, new ParameterizedTypeReference<List<PartnerShipmentDto>>() {});

但我在restTemplate.postForObject中得到了错误下划线，看起来像这样：

中的方法postForObject(String，Object，Class，Object…(类型RestTemplate不适用于参数(String，HttpEntity，新参数化类型引用<列表>((｛｝(

我应该更改什么来修复此问题？

Answer 1

如果要使用ParameterizedTypeReference<T>，则需要使用RestTemplate.exchange()，因为这是唯一公开类型为ParameterizedTypeReference<T>的参数的方法。

List<PartnerShipmentDto> partnerShipmentDto = restTemplate.exchange(url, 
HttpMethod.GET, 
requestPartnerShipmentDto,
new ParameterizedTypeReference<List<PartnerShipmentDto>>() {})
.getBody();