我正试图用reduce函数解决我的最后一个问题,将嵌套的JSON对象转换为平面列表,以便更容易地进行搜索。
获取下方的JSON
{
"MovementPatterns": [
{
"Id": "",
"Name": "Warm-up",
"Exercises": [
{
"Id": "",
"Name": "Lizard Stretch",
"Level": 1,
"EquipmentRequired": ""
},
{
"Id": "",
"Name": "Pigeon Stretch",
"Level": 1,
"EquipmentRequired": ""
},
{
"Id": "",
"Name": "Core Hold",
"Level": 1,
"EquipmentRequired": ""
},
{
"Id": "",
"Name": "Superman",
"Level": 1,
"EquipmentRequired": ""
}
]
},
{
"Name": "Horizontal Push",
"Id": "",
"Exercises": [
{
"Id": "",
"Name": "Wall Push-up",
"Level": 0,
"VideoUrl": "",
"EquipmentRequired": ""
},
{
"Id": "",
"Name": "Push-up",
"Level": 1,
"EquipmentRequired": ""
},
{
"Id": "",
"Name": "Tap Push-up",
"Level": 2,
"EquipmentRequired": ""
},
{
"Id": "",
"Name": "Explosive Push-up",
"Level": 3,
"EquipmentRequired": ""
}
]
}
]
}
我使用了以下代码:
const exercises = data.MovementPatterns.reduce(
(a, {Exercises}) => [...a, ...Exercises, ...a],
[],
);
将每个动作模式中的所有练习精简为一个纯粹的练习列表。。。这很好,但我现在需要在每个练习的JSON中包含父母运动模式ID,例如
[
{
"Id": "",
"Name": "Lizard Stretch",
"Level": 1,
"MovementPatternId": 1,
"EquipmentRequired": ""
},
....
{
"Id": "",
"Name": "Wall Push-up",
"Level": 1,
"MovementPatternId": 2,
"EquipmentRequired": ""
},
]
有人能帮我弄清楚如何使用我的reduce函数吗:(
感谢
您已接近尾声。只需将父元素的Id
作为MovementPatternId
附加到Exercises
的每个元素即可。
const exercises = ab.MovementPatterns.reduce(
(a, { Exercises, Id }) => [
...a,
...Exercises.map(e => ({ ...e, MovementPatternId: Id }))
],
[]
);