如何在同一位置打印两个setfill()

Question

我试图用setfill()和setw()练习左右对齐，但我遇到了一个问题：我无法用-字符打印出~字符。

#include <iostream>
#include <iomanip>
#include <string>
using namespace std;
typedef struct kereta{
string brand, model;
int year;
float price;
}car;
int main(){

kereta car[100];
int num,i;

cout<<"How many cars?: ";
cin >>num;

for(i=0;i<num;i++){
cout<<"Insert brand for car "<<i+1<<": ";
cin>>car[i].brand;
cout<<"Insert model for car "<<i+1<<": ";
cin>>car[i].model;
cout<<"Insert year for car "<<i+1<<": ";
cin>>car[i].year;
cout<<"Insert price for car "<<i+1<<": ";
cin>>car[i].price;
cout<<endl;
}
for(i=0;i<num;i++){
cout<<fixed;
cout<<car[i].brand<<right<<setfill('*')<<setw(10);
cout<<car[i].model<<right<<setfill('-')<<setw(10);
cout<<car[i].year<<setfill('~')<<setw(15)<<right<<setfill('.')<<setw(15);
cout<<showpoint<<setprecision(3)<<car[i].price;
cout<<endl;
}

}

我正在尝试将输出作为：

**Proton****Hahaha~~~~------2004......40000.000**

但我得到的却是：

**Proton****Hahaha------2004......40000.000**

Answer 1

您应该分部分考虑输出。setw和其他输出操纵器为下一个流的数据设置参数。

cout << left << setfill('*') << setw(10) << car[i].brand;
cout << left << setfill('~') << setw(10) << car[i].model;
cout << right << setfill('-') << setw(15) << car[i].year;
cout << right << setfill('.') << setw(15) << setprecision(3) << showpoint << car[i].price;