我通过Servlet上的AJAX使用Jsp发送表单数据
reg.jsp
<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Insert title here</title>
</head>
<body>
<form>
Enter name:<input type="text" id="name" /> <br />
<button onclick="callJqueryAjax()">Save</button>
</form>
<span id="result"></span>
<script
src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<script type="text/javascript">
function callJqueryAjax() {
location.reload(false);
var name = $('#name').val();
console.log(name);
$.ajax({
url : 'Save',
method : 'POST',
data : {
name : name,
},
success : function(resultText) {
$("#result").html(resultText);
}
});
}
</script>
</body>
</html>
SaveMe.java
import java.io.IOException;
import java.io.PrintWriter;
import java.sql.Connection;
import java.sql.SQLException;
import java.sql.Statement;
import javax.servlet.ServletConfig;
import javax.servlet.ServletException;
import javax.servlet.ServletRequest;
import javax.servlet.ServletResponse;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
@WebServlet("/Save")
public class SaveMe extends HttpServlet {
private static final long serialVersionUID = 1L;
private Connection makeCon;
private Statement stmt;
public void init(ServletConfig config) throws ServletException {
JdbcCon jdbcCon = new JdbcCon();
makeCon = jdbcCon.makeCon();
try {
stmt = makeCon.createStatement();
} catch (SQLException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
protected void doPost(HttpServletRequest request, HttpServletResponse res) throws ServletException, IOException {
String name = request.getParameter("name");
res.setContentType("text/html");
PrintWriter out = res.getWriter();
String sql = "insert into users (name) Values('" + name + "')";
System.out.println(sql);
try {
int result = stmt.executeUpdate(sql);
if (result > 0) {
out.print("Inserted");
} else
out.print("Not Inserted");
} catch (SQLException e) {
}
}
}
我在ajax中接收输出，但问题是JSP自己重新加载，删除响应，并从Textbox中删除数据，我的响应会从中自行消失。
请为我提供解决方案，以及编写ajax调用的更好方法
首先我不明白你为什么要使用"location.reload(false("在提交ajax请求之前，在您的JSP页面中。你可以删除它。此外，当使用ajax请求时，一个好的实践是指定"；dataType"；，在你的情况下"；html"；。这里有一个例子：
$.ajax( {
type : 'POST',
url : 'SaveMe',
success : function(result) {
$("#result").html(result);
},
dataType : "html"
});