我还能如何格式化数据?swift parse无法读取数据，因为它的格式不正确

Question

JSON数据是

[
{"id":0,"temperature":77,"humidity":0.22,"timeCaptured":"2020-09-25T19:33:27.9733333"},
{"id":0,"temperature":77,"humidity":0.22,"timeCaptured":"2020-09-25T20:38:53.3"},
{"id":0,"temperature":85,"humidity":0.25,"timeCaptured":"2020-09-25T20:38:53.3"},
{"id":0,"temperature":88,"humidity":0.22,"timeCaptured":"2020-09-28T15:30:00"},
// ...
]

我的结构看起来像这个

struct TemperatureDataModel: Codable{
let id:              Int?
let temperature:     Double?
let humidty:         Double?
let timeCaptured:    String?
}

我的功能看起来像这个

func getTemperData(){
//Create the URLs
let temperatureDataUrl = URL(string: "https://weatherstationapi.azurewebsites.net/api/TemperatureSensor/GetData")
// let WindDataUrl = URL(string: "https://weatherstationapi.azurewebsites.net/api/WindData/GetAllData")
guard let requestURLTemp = temperatureDataUrl else { fatalError() }
//Create URL request
var request = URLRequest(url: requestURLTemp)
//Specifiy HTTP Method to use
request.httpMethod = "GET"
request.setValue("application/json", forHTTPHeaderField: "Accept")
request.setValue("Bearer         eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJodHRwOi8vc2NoZW1hcy54bWxzb2FwLm9yZy93cy8yMDA1LzA1L2lkZW50aXR5L2NsYWltcy9uYW1lIjoiaWxpci50YWlyaUB0dHUuZWR1IiwiaHR0cDovL3NjaGVtYXMueG1sc29hcC5vcmcvd3MvMjAwNS8wNS9pZGVudGl0eS9jbGFpbXMvbmFtZWlkZW50aWZpZXIiOiI4MjEzYzhhMy1iODgxLTQ4NmUtOGUyMC1mZmNlMDlmNGY0ZjgiLCJuYmYiOiIxNjAyNTI2NDI1IiwiZXhwIjoiMTYwNTExODQyNSJ9.t1qnYyXLpRRJ3YQfhgLrylBqL_pdKOnKVMgOfG9IuVc", forHTTPHeaderField: "Authorization")
//Send HTTP Request
let task = URLSession.shared.dataTask(with: request) { (data, response, error) in
guard let data = data else {return}
print(data)
//Use parseJSON to convert data
let TemperatureData = parseJSON(data: data)
// for singleValue in TemperatureData {
//     print(singleValue.temperautre)
// }
//read list
guard let TemperatureDataModel = TemperatureData else {return}
print("Temperature is : (TemperatureDataModel.temperature)")

// Check if error took place
if let error = error {
print("Error took place (error)")
return
}
//Read HTTP Response Status Code
// if let data = data, let dataString = String(data: data, encoding: .utf8) {
//    print("Response data string:n (dataString)")
// }
}
task.resume()
}

然后我的JSON解码器函数看起来像这个

func parseJSON(data: Data) -> TemperatureDataModel? {    
var returnValue: TemperatureDataModel?
do {
let returnValue = try JSONDecoder().decode([TemperatureDataModel].self, from: data)
} catch {
print("Error took place (error).")
}
return returnValue
}

我现在已经看了6+堆栈溢出的帖子，但仍然无法弄清楚。我试着把我的模型放在[]中作为一个数组，移动函数的调用位置，更改jsondecoder函数等等，但都不起作用。

Answer 1

我认为在解析数据之前，必须为日期提供一种格式

let dateFormatter=dateFormatter((dateFormatter.dateFormat="yyyy-MM-dd’T'HH:MM:ssZ"；

Answer 2

问题是您正在创建另一个未返回的returnValue。您还需要将退货类型更改为[TemperatureDataModel]

func parseJSON(data: Data) -> [TemperatureDataModel]? {
do {
return try JSONDecoder().decode([TemperatureDataModel].self, from: data)
} catch {
print("Error took place (error).")
return nil
}
}