如何每天运行两次R脚本

Question

我有一个R脚本，配置为每天上午10点通过cron运行

library(cronR)
cmd2 = cron_rscript("CargueDiario_RedcapCovid_ODS.R", rscript_log="/home/admonda/R/projects/contagios_covid_santander/log/cargue_diario.log", log_append = T, log_timestamp = T)
cron_add(command = cmd2, frequency = 'daily', at = "10:00" , days_of_week = "*", id = 'FCVREDCAPCOVID_ODS_DIARIO', description = "FCVREDCAPCOVID_ODS_DIARIO")
cron_ls("FCVREDCAPCOVID_ODS_DIARIO")
## cronR job
## id:   FCVREDCAPCOVID_ODS_DIARIO
## tags: 
## desc: FCVREDCAPCOVID_ODS_DIARIO
0 10 * * 0,1,2,3,4,5,6 /usr/lib/R/bin/Rscript '/home/admonda/R/projects/contagios_covid_santander/CargueDiario_RedcapCovid_ODS.R'  >> '/home/admonda/R/projects/contagios_covid_santander/log/cargue_diario.log' 2>&1

现在我需要更改它，使它每天运行两次(10:00和22:00(。我已经从CRON中删除了它，我想确保这是正确的新命令：

cron_add(command = cmd2, frequency = 'daily', at = c("10:00","22:00") , days_of_week = "*", id = 'FCVREDCAPCOVID_ODS_DIARIO', description = "FCVREDCAPCOVID_ODS_DIARIO")

Answer 1

cron_add(command = cmd2, frequency = 'daily', at = 'c(10,22)', days_of_week = '*', id = '...', description = '...')

或者只使用cron表达式：

cron_add(cmd, frequency = '0 10,22 * * *', id = '...', description = '...')

来源：https://www.rdocumentation.org/packages/cronR/versions/0.4.2/topics/cron_add

Answer 2

您仍然可以使用原始行，只需将10更改为10,22即可。

0 10,22 * * * /usr/lib/R/bin/Rscript '/home/admonda/R/projects/contagios_covid_santander/CargueDiario_RedcapCovid_ODS.R'  >> '/home/admonda/R/projects/contagios_covid_santander/log/cargue_diario.log' 2>&1 >/dev/null 2>&1