javascript执行超时

Question

我有两个正在写JS的文件：学习和测试。学习后，我尝试创建一个asyc函数，该函数将执行以下操作：
开发一个名为"qAsync"的"函数声明">
返回一个由两个键组成的对象(通过构造函数构建(：

1. "doAsync"：函数：返回可以使用async/await语法使用的setTimeout函数
2. "exec"：使用doAsync函数在11.5秒后打印内容的函数
3. "desc"：string：doAsync/exec((正在做什么以及如何使用它的描述

但我不确定我的代码是否正确，因为我的测试文件由于某种原因无法识别我的exec。我在learn.js:上的代码

function qAsync(){
const doAsync = new doAsync(11500);
this.desc= "in order to wait 11.5 sec, call qAsync which calls asyncFun"
let exec= doAsync.exec(("hello after 11.5 sec"));
return (exec,doAsync);
}

let doAsync = async function (ms) {
return await new Promise(resolve => setTimeout(resolve, ms));
}

测试.js:

function test4(){
let test = qAsync();
alert("first let us decribe the function:n" + test.desc);
alert("now we will run exec.");
test.exec(); //doesn't work and calls on built in exec and not mine
}

我如何才能让我的测试工作，你认为我应该改进我的qAsync吗？

Answer 1

感谢评论回答：learn.js:

function qAsync(){
this.doAsync = function (ms) {
return new Promise(resolve => setTimeout(resolve, ms));
}
this.desc = "in order to wait 11.5 sec, call exec which calls doAsync, and see the print in the console"
this.exec =  async function () {
await this.doAsync(11500);
console.log("did you see this after 11.5 sec?");
}
}

test.js:

async function test4(){
let test = new qAsync();
alert("first let us describe the function:n"+test.desc);
alert("now we will run exec.");
await test.exec();
}