棱镜:模型和关系1-n



我有两个表UserTasks,一个用户可以有很多任务,但我希望查询返回一个特定的任务,从用户表中获取任务的详细信息,以及作者和分配给用户的信息,通常会使用别名来完成。DB是mysql-感谢

//schema.prisma
model User {
id         Int    @id @default(autoincrement())
taskby     Task[] @relation("taskBy")
taskto     Task[] @relation("taskTo")
}
model Task {
id              Int      @id @default(autoincrement())
created_at      DateTime @default(now())
updated_at      DateTime @updatedAt
assigned_to_uid Int
assigned_by_uid Int
assigned_to     User     @relation("taskTo",fields: [assigned_to_uid], references: [id])
assigned_by     User     @relation("taskBy",fields: [assigned_by_uid], references: [id])
}

API:

if (id) {
res = await prisma.task.findUnique({
where: { id },
include: {
assigned_to: true
},
include: {
assigned_by: true
},
})
} else {...

期望响应:

{
"id": 2,
"taskid": 2,
"assigned_to_uid": 1,
"assigned_by_uid": 2,
"assigned_by": {
"id": 2,
"firstName": "user2",
},
"assigned_to": {
"id": 1
"firstName": "user1",
},
}

您应该能够使用以下查询获得所需的响应:

if (id) {
const response = await prisma.task.findUnique({
where: { id },
include: {
assigned_to: true,
assigned_by: true,
},
});
console.log(response);
}

对上述查询的响应:

{
id: 1,
created_at: 2022-02-28T07:22:06.917Z,
updated_at: 2022-02-28T07:22:06.918Z,
assigned_to_uid: 2,
assigned_by_uid: 1,
assigned_to: { id: 2, firstName: 'Jane', lastName: 'Doe' },
assigned_by: { id: 1, firstName: 'John', lastName: 'Doe' }
}

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