删除重复项时保留数字

Question

这是我在字符串中删除重复字母的代码

word=input()
def dup_find(word):
empty = ""  
for character in word:
if character not in empty or character == " ":
empty = empty + character
return empty

当输入为"0"时；6969通心粉"；输出为"0"；69 macroni"；但我希望数字保持不变，只删除重复的字母so：6969 macroni。

谢谢你的帮助。

Answer 1

这是的正确方式

text="Enter string:"+" "
string=input(text)
def rem_duplicates(string):
x = ""  
for letter in string:
if letter.isdigit() or letter not in x or letter == ' ':
x = x + letter
return x
print(rem_duplicates(string))

Answer 2

试试这个：

text = "Enter string: " # just do the space in the string
string = input(text)

def rem_duplicates(string):
x = ""
for letter in string:
if letter.isdigit() or letter not in x or letter == " ": # if the string is a number or letter is empty or letter not in x
x = x + letter
return x

print(rem_duplicates(string))

Answer 3

检查是否来自字符串isnumeric()的字母，然后设置条件。letter == ' '不是必需的，但您也可以设置。

text = "Enter string:"+" "
string = input(text)
def rem_duplicates(string):
x = ""
for letter in string:
if letter.isnumeric() or letter not in x or letter == ' ':
x = x + letter
return x

print(rem_duplicates(string))