我正在努力迎接这个挑战:
设计函数month_name,它接受1到12之间的数字,并输出相应的月份名称。例如,给定数字2,函数应该打印二月。当给定一个无效数字时,你的函数不应该打印任何东西。函数应该使用if语句,不应该使用字典
到目前为止我只有这个:
# A month_name is a number -> string
# takes in a number and gives the coresponding month
def month_name(number1):
1 = January
2 = Febuary
3 = March
4 = April
5 = May
6 = June
7 = July
8 = August
9 = Suptember
10 = October
11 = November
12 = December
首先,您不应该为数字或保留关键字赋值。这适用于任何编程语言
Python已经有一个定义良好的库集。在这种情况下,我建议使用calendar
import calendar
calendar.month_name(<month_number_here>)
如果你想冒险,可以使用列表或字典。
month_list = ['January', 'Febr......, 'December']
或
month_list = {1:January, 2:February, ...., 12:December}
如果列表索引从0开始查找month_list[<month_number_here> - 1]
字典查找month_list(<month_number_here>)